3 years ago

In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and

1 answer:

7 0

m∠CED = 1/2(m∠AOB + m∠COD) = 1/2(90° + 16°) = 1/2(106°) = 53°

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