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Tanzania [10]
3 years ago
9

In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and

Mathematics
1 answer:
Romashka [77]3 years ago
7 0
<span>m∠CED = </span><span>1/2(m∠AOB + </span><span><span>m∠COD)</span> = 1/2(90° + 16°) = 1/2(106°) = 53°</span>

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SImplify to standard form (a+bi)<br> (12-9i)²
olga2289 [7]

Answer:

Hello,

Step-by-step explanation:

<u />

<u>Formula used (a+b)^2=a²+2ab+b²</u>

(12-9i)^2=3^2*(4-3i)^2\\\\=9*(16-9-24i)\\\\=9*(7-24i)\\\\=63-216i\\

5 0
3 years ago
Find the slope of the line passes through the pair of points (-5.5,6.1), (-2.5,3.1)
skad [1K]
The answer would be C.

If you do -5.5 + 2.5 over 6.1 - 3.1 it would be -3 over 3 which is equal to -1.

You could also do -2.5 + 5.5 over 3.1 - 6.1. It would be 3 over -3 which is also equal to -1.
7 0
2 years ago
How could you rewrite (-3 + 5) + 8 + (-1)
vagabundo [1.1K]

(-3 + 5) + 8 + (-1)=

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7 0
2 years ago
Not sure how I would solve this
suter [353]
<h3>Answers:</h3>

The first ordered pair is   ( -4 , -3 )

The second ordered pair is   ( 8, 3 )

=================================================

Explanation:

The first point is (x,-3) where x is unknown. It pairs up with y = -3 so we can use algebra to find x

x-2y = 2

x-2(-3) = 2 ... replace every y with -3; isolate x

x+6 = 2

x = 2-6

x = -4

The first point is (-4, -3)

---------------------------

We'll do something similar for the other point. This time we know x but don't know y. Plug x = 8 into the equation and solve for y

x-2y = 2

8-2y = 2

-2y = 2-8

-2y = -6

y = -6/(-2)

y = 3

The second point is (8, 3)

4 0
3 years ago
Convert 2x-y=-7 into slop-intercept form​
kykrilka [37]
I believe the answer is y=2x+7
7 0
2 years ago
Read 2 more answers
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