Question

In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and

Answer 1

m∠CED = 1/2(m∠AOB + m∠COD) = 1/2(90° + 16°) = 1/2(106°) = 53°