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Studentka2010 [4]
3 years ago
7

the values in the table represent an exponential function what is the common ratio of the associated geometric sequence​

Mathematics
1 answer:
zmey [24]3 years ago
3 0

Answer:

B. 6

Step-by-step explanation:

6 x 6 = 36

36 x 6 = 216

216 x 6 = 1296

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For each pair of similar figures, find the ratio of the area of the first figure to the area of the second.
Hitman42 [59]

answer:

\frac{4}{9}


explanation:

the area of the larger square is 36 (6*6), and the area of the smaller square is 16 (4*4). to find the ratio of the area, simply just put 16 over 36 and simplify.

\frac{16}{36} = \frac{4}{9}

--

if this helped, please consider giving brainliest !

7 0
3 years ago
PLEASE HELP ME THIS IS DUE ASAP!!! I will mark brainliest if right!!! Explain!
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Answer:

Step-by-step explanation:

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3 years ago
A gallon of gas costs $2.73. Walter pays for 24 gallons of gas. He gives the clerk $80.00. How much change should Walter receive
wolverine [178]

Answer:

14.48

Step-by-step explanation:

2.73×24=65.52 is how much 24 gallons cost.

80.00-65.52=14.48 this how much money he would get back from paying for gas

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7 0
3 years ago
What is 19 divided by 20 using long division & decimals?
andrew-mc [135]

Answer:

0.95

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3 0
3 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
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