Problem 1
We'll use the product rule to say
h(x) = f(x)*g(x)
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
Then plug in x = 2 and use the table to fill in the rest
h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)
h ' (2) = f ' (2)*g(2) + f(2)*g ' (2)
h ' (2) = 2*3 + 2*4
h ' (2) = 6 + 8
h ' (2) = 14
<h3>Answer: 14</h3>
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Problem 2
Now we'll use the quotient rule

<h3>Answer: -2/9</h3>
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Problem 3
Use the chain rule

<h3>Answer: 12</h3>
ANSWER

EXPLANATION
The required equation passes through:
(4,3) and is perpendicular to x+y=4.
Rewrite the given equation in slope-intercept form:

The slope of this line is -1.
The slope of the required line is perpendicular to this line, so we find the negative reciprocal of this slope.

The equation of the line can be found using:

We substitute the slope and point to obtain:

We simplify to get:


The required equation is
I believe the expression would be 7(g)+7
Mathematics is the subject that is most popular in the class and is liked by the students.
<u>Explanation:</u>
Among all the subjects that are added in the curriculum of the students in the school, Mathematics is the subject that is mostly liked by the students in the class and in the school.
To find this that mathematics was the favorite subject of the students, a a survey was conducted by the school people in the class of a professor and through that survey it was shown that Mathematics was a subject that was mostly liked by all the students.
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.