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Ray Of Light [21]

2 years ago

12

A coin weighs 4/15 ounces. A different coin weighs 1/15 ounces. How much do the two coins weigh together? Write your answer as a

fraction in simplest form.

1 answer:

olchik [2.2K]2 years ago

7 0

Answer:

1/3

Step-by-step explanation:

4/15 + 1/15 = 5/15

simplified its 1/3

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HELP ASAP IM STRUGGLING : The instructions on a box of chicken patties state that one patty should be cooked for 2.5 minutes in

AveGali [126]

Answer:

y= 1.5x + 2.5

Step-by-step explanation:

So slope intercept form is y= mx + b.

y is the number of minutes, so that will be on the left of the equal sign, not part of the math side of the actual equation, because it's the answer.

1.5x is the mx part because it's 1.5 minutes for each extra patty. So that would explain the x attached to it. so for each extra patty you add, that's what x would be.

The + 2.5 at the end, is just the time for the initial patty.

Hope this helps and is easy to understand! :)

4 0

3 years ago

The perimeter of an isosceles trapezoid is 28 in and the ratio of lengths of its bases is 5:3. Find the lengths of the sides of

Natalka [10]

The measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches

Let x = length of base and leg

The formula for perimeter of isosceles trapezoid is P = b₁ + b₂ + 2(leg)
Where: b = base

   P = b₁ + b₂ + 2(leg)
   28 = 3x + 5x + 2(x)
   28 = 8x + 2x
28/10 = 10x/10
2.8 = x

Now, substitute the values:
     P = b₁ + b₂ + 2(leg)
   28 = 3(2.8) + 5(2.8) + 2(2.8)
28 = 8.4 + 14 + 5.6
28 = 28

Hence the measurements are:
b₁ = 8.4 inches; b₂ = 14 inches; leg₁ = 2.8 inches; leg₂ = 2.8 inches

8 0

2 years ago

Find the measures of the angles of the triangle whose vertices are A = (-3,0) , B = (1,3) , and C = (1,-3).A.) The measure of ∠A

alekssr [168]

Answer:

$\theta_{CAB}=128.316$

$\theta_{ABC}=25.842$

$\theta_{BCA}=25.842$

Step-by-step explanation:

A = (-3,0) , B = (1,3) , and C = (1,-3)

We're going to use the distance formula to find the length of the sides:

$r= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

$AB= \sqrt{(-3-1)^2+(0-3)^2}=5$

$BC= \sqrt{(1-1)^2+(3-(-3))^2}=9$

$CA= \sqrt{(1-(-3))^2+(-3-0)^2}=5$

we can use the cosine law to find the angle:

it is to be noted that:

the angle CAB is opposite to the BC.

the angle ABC is opposite to the AC.

the angle BCA is opposite to the AB.

to find the CAB, we'll use:

$BC^2 = AB^2+CA^2-(AB)(CA)\cos{\theta_{CAB}}$

$\dfrac{BC^2-(AB^2+CA^2)}{-2(AB)(CA)} =\cos{\theta_{CAB}}$

$\cos{\theta_{CAB}}=\dfrac{9^2-(5^2+5^2)}{-2(5)(5)}$

$\theta_{CAB}=\arccos{-\dfrac{0.62}}$

$\theta_{CAB}=128.316$

Although we can use the same cosine law to find the other angles. but we can use sine law now too since we have one angle!

To find the angle ABC

$\dfrac{\sin{\theta_{ABC}}}{AC}=\dfrac{\sin{CAB}}{BC}$

$\sin{\theta_{ABC}}=AC\left(\dfrac{\sin{CAB}}{BC}\right)$

$\sin{\theta_{ABC}}=5\left(\dfrac{\sin{128.316}}{9}\right)$

$\theta_{ABC}=\arcsin{0.4359}\right)$

$\theta_{ABC}=25.842$

finally, we've seen that the triangle has two equal sides, AB = CA, this is an isosceles triangle. hence the angles ABC and BCA would also be the same.

$\theta_{BCA}=25.842$

this can also be checked using the fact the sum of all angles inside a triangle is 180

$\theta_{ABC}+\theta_{BCA}+\theta_{CAB}=180$

$25.842+128.316+25.842$

$180$

6 0

2 years ago

Read 2 more answers

Find the distance between (3,4) and (4,-6) if necessary, round to the nearest tenth.

Ratling [72]

Answer:

The distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

Step-by-step explanation:

Given the points

(3,4)

(4,-6)

The distance 'd' between (3,4) and (4,-6)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):$

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

substituting the points values

$=\sqrt{\left(4-3\right)^2+\left(-6-4\right)^2}$

$=\sqrt{1+10^2}$

$=\sqrt{1+100}$

$=\sqrt{101}$

$=10.0$ units (Rounded to the nearest the Tenths Place)

Thus, the distance is:

d = 10.0 units (Rounded to the nearest the Tenths Place)

4 0

2 years ago

I need help for this question.

sattari [20]

Answer:

B

Step-by-step explanation:

The figure is a trapezium with area (A) calculated as

A = $\frac{1}{2}$ h (a + b)

where h is the perpendicular height and a, b the parallel bases

Here h = 8, a = 10 and b = 6, thus

A = $\frac{1}{2}$ × 8 × (10 + 6) = 4 × 16 = 64 cm² → B

4 0

2 years ago