Answer:
x ≤ 2
Step-by-step explanation:
If you referencing ">=" as greater than or equal to, follow the solution below:
Solve:
3x - 6 + 2 ≥ 5x - 8
Combine like terms.
3x - 4 ≥ 5x - 8
Subtract 5x from both sides.
-2x - 4 ≥ -8
Add 4 to both sides.
-2x ≥ -4
Divide both sides by -2, while flipping the inequality as well since you're dividing by a negative number.
x ≤ 2
Your answer would be x ≤ 2
Answer:
Correct answer: B
Step-by-step explanation:
Syntax: in piecewise functions such as the one attached, the "if:" section shows the domain, or x-axis values which that function pertains to.
In the graph, you can see that the graph is defined for 
(not-including 1 because there is an open hole there, indicating it is not part of the domain), and 
.
Now that we know the domain, we can attach it to the graphs that lie on those domains.
We see that the leftmost line appears to have a positive slope and a negative y-intercept, and that the second line should have a positive y-intercept and a negative slope.
At this point, you can just start crossing off answers that don't meet this criteria.
Cheers!!
Answer:
k = 15
Step-by-step explanation: pls thank me and mark me brainliest :3
Add 31 to both sides which will give you
9h = 130
Answer:
(115.2642, 222.7358).
Step-by-step explanation:
Given data:
type A: n_1=60, xbar_1=1827, s_1=168
type B: n_2=180, xbar_2=1658, s_2=225
n_1 = sample size 1, n_2= sample size 2
xbar_1, xbar_2 are mean life of sample 1 and 2 respectively. Similarly, s_1 and s_2 are standard deviation of 1,2.
a=0.05, |Z(0.025)|=1.96 (from the standard normal table)
So 95% CI is
(xbar_1 -xbar_2) ± Z×√[s1^2/n1 + s2^2/n2]
=(1827-1658) ± 1.96×sqrt(168^2/60 + 225^2/180)
= (115.2642, 222.7358).
