y=x+14 line 1
y=3x+2 line 2
These are both the equation of lines written in slope intercept form
y=mx+b where m is the slope and the point (0,b) is the y intercept.
The first line has a slope of m=1. The 2nd line has a slope of m=3
Since these lines have different slopes, they are not parallel, thus they will cross at some point. What you have to determine is where the lines cross, which will be a point (x,y) that is on both lines.
We already have y solved in terms of x from either equation so we can use substitution to solve the system.
Since y=x+14 from line 1, put x+14 in place of y in the equation of line 2.
x+14=3x+2
solve for x.
Subtract x from both sides...
14= 3x-x+2
14=2x+2
subtract 2 from both sides
14-2=2x
12=2x
divide both sides by 2
6=x
We now have the x value of the common point. Plug the value 6 in for x in one of the original equations and solve for y.
y=6+14
y=20
These two lines cross at the point (6,20) which is a point the two lines have in common.
Hope I helped (SharkieOwO)
9514 1404 393
Answer:
C. (-4, -3)
Step-by-step explanation:
The point where the lines cross is the solution to both equations. That point is in the third quadrant, where both coordinate values are negative.
The x-coordinate of the point is listed first, so the solution is ...
(x, y) = (-4, -3)
Answer:
The parenthesis means to multiply the numbers. I don't understand any of these either but I hope this helps.
Step-by-step explanation:
Answer:
open circle
Step-by-step explanation:
the open circle does not include the number. this is what you want because the solution is not equal to the number
