What’s the answer ??? V/8=5-3

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago

I need help again with these Please and thank you 17points

Juli2301 [7.4K]

6 3/14

Is the correct mixed number

6 0

3 years ago

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1/3x+y=4 help please?

professor190 [17]

$\frac{1}{3}x+y=4\ \ \ \ \ |subtract\ \frac{1}{3}x\ from\ both\ sides\\\\y=4-\frac{1}{3}x$

8 0

3 years ago

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How do you graph: y≤−4x+40 and y≤10

Arturiano [62]

Answer:

See attached picture.

Step-by-step explanation:

To graph linear inequalities, use the y=mx + b form to graph using the slope and y-intercept.

y ≤ -4x + 40 has slope -4 and y-intercept (0,40).

Start at (0,40) and mark it. Then move down 4 units and to the right 1. Mark this point at (1,36). Connect the points with a solid line since the inequality has equal to. Substitute a point like (0,0) to test where the solution set is.

0 ≤ -4(0) + 40

0 ≤ 0 + 40

0 ≤ 40

This is true so shade to the left of the line.

To graph y ≤ 10 mark a point on the y-axis at (0,10). Draw a horizontal solid line through the point. Then shade below the line.

7 0

3 years ago

I just need the answers you don’t have to explain for number 4

jolli1 [7]

C- 8
D- 8i
E- 11

Those are all the ones I know, mark as brainliest pls :)

4 0

4 years ago

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