Answer:
(a) 
(b) 
(c) P(X ≤ 1) = 0.6321
(d) P(2 ≤ X ≤ 5) = 0.1286
Step-by-step explanation:
From the given information; Let consider X to be the time between two successive arrivals at the drive-up window of a local bank.
However; If X is regarded as the exponential distribution with λ = 1 which is identical to a standard gamma distribution with ∝ = 1
The objective is to compute the following :
(a) The expected time between two successive arrivals is;



(b) The standard deviation of the time between successive arrivals is;




(c) P(X ≤ 1)
P(X ≤ 1) = 1 - e⁻¹
P(X ≤ 1) = 0.6321
(d) P(2 ≤ X ≤ 5)
P(2 ≤ X ≤ 5) = [1 - e⁻⁵] - [1 - e⁻²]
P(2 ≤ X ≤ 5) = 0.9933 - 0.8647
P(2 ≤ X ≤ 5) = 0.1286
Answer:
Step-by-step explanation:
you have to add a table
Hey there!

squared would equal = 4096.
Your correct answer would be
. . .

Hope this help you.
~Jay







The first case occurs in

for

and

. Extending the domain to account for all real

, we have this happening for

and

, where

.
The second case occurs in

when

, and extending to all reals we have

for

, i.e. any even multiple of

.