What are the terms in this expression 3+4x5

Solve for b2 in A = 1/2 h(b1+b2), if A = 16, h = 4, and b1 = 3. 16= 1/2* 4(3+b2) =6+2b2 or, b2= [16-6]/2= 5

Tatiana [17]

Assuming you are referring to the area of a "trapezoid"; in which one calculates the Area, "A", as follows:
________________________
 A = 1/2* h(b1+b2) ;

in which: A = Area = 16 (given);
h = height = 4 (given);
b1 = length of one of the two bases = 3 (given);
b2 = length of the other of the two bases = ? (what we want to solve for) ;
______________________________________________________
Using the formula: A = 1/2 h(b1+b2) ;
________________________________
Let us plug in our known values:
___________________________
→ 16 = (1/2) * 4*(3 + b2) ; → Solve for "b2".
________________________________
→Note: On the "right-hand side" on this equation: "(1/2)*(4) = 2 ."
________________________________
So, we can rewrite the equation as:
________________________________
→ 16 = 2*(3 + b2) ; → Solve for "b2".
________________________________
We can divide EACH side of the equation by "2"; to cancel the "2" on the "right-hand side" of the equation:
________________________________
→ 16 / 2 = [2*(3 + b2)] / 2 ; → to get:
___________________________
8 = (3 + b2) ;
_________________
→ Rewrite as: 8 = 3 + b2;
_______________________
Subtract "3" from EACH side of the equation; to isolate "b2" on one side of the equation; and to solve for "b2" :
______________________________
→ 8 - 3 = 3 + b2 - 3 ; → to get:
_____________________
b2 = 5; From the 2 (TWO) answer choices given, this value,
"b2 = 5", corresponds with the following answer choice:
____________________
b2= [16-6]/2= 5 ; as this is the only answer choice that has: "b2 = 5".
_________________________________________

As far getting "b2 = 5" from: "b2= [16-6]/2= 5"; (as mentioned in the answer choice), we need simply to approach the problem in a slightly different manner. Let us do so, as follows:
_____________________________________
Start from: A = 1/2 h(b1+b2); and substitute our known (given) values):
________________________
→ 16 = (1/2) *4 (3 + b2) ; → Solve for "b2".
_____________________________
Note that: (½)*4 = 2; so we can substitute "2" for: "(1/2) *4" ;
and rewrite the equation as follows:
_________________________
→ 16 = 2 (3 + b2) ;
____________________
Note: The distributive property of multiplication:
_________________________
a*(b+c) = ab + ac ;
_________
As such: 2*(3 + b2) = (2*3 + 2*b2) = (6 + 2b2).
_________________
So we can substitute: "(6 + 2b2)" in lieu of "[2*(3 + b2)]"; and can rewrite the equation:
______________________
→ 16 = 6 + 2(b2) ; Now, we can subtract "6" from EACH side of the equation; to attempt to isolate "b2" on one side of the equation:
________________________________________________
→ 16 - 6 = 6 + 2(b2) - 6 ;
→ Since "6-6 = 0"; the "6 - 6" on the "right-hand side" of the equation cancel.
→ We now have: 16 - 6 = 2*b2 ;
___________
Now divide EACH SIDE of the equation by "2"; to isolate "b2" on one side of the equation; and to solve for "b2":
____________________
→ (16 - 6) / 2 = (2*b2) / 2 ;
→ (16 - 6) / 2 = b2 ;
→ (10) / 2 = b2 = 5.
______________
NOTE: The other answer choice given:
_____________
"16= 1/2* 4(3+b2)= 6+2b2" is incorrect; since it does not solve for "b2".

3 0

3 years ago

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i dont know how to solve this questions without a graphing on a calculator but i can't use calculator for this question pls help

hoa [83]

Answer:

D

Step-by-step explanation:

When the denominator is equal to 0, the function doesn't exist. So factor the bottom, luckily its already partially factored.

(x^2 + 8x + 12) = (x+2)(x+6)

So now the denominator is (x+2)(x+6)(x-3)

The function doesn't exist when x = -2, -6, 3

Now we know there are 3 total discontinuities.

A and B can be eliminated

Since there is an (x+2) on the top and the bottom, they don't affect the shape of the function, but only causes a removable discontinuity when x = -2.

However, (x+6) and (x-3) are only on the bottom, so they DO change the shape, so they are non-removable

The answer therefore is 1 removable and 2 non-removable; D

7 0

3 years ago

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HELP ME FAST. I’ll give thanksss. please i’m lost

Fudgin [204]

9514 1404 393

Answer:

24°

Step-by-step explanation:

The angle between the vertical line AB and the horizontal dashed line at A is 90°. That is, ...

66° + ? = 90°

? = 90° -66° = 24°

The angle of depression is 24°.

_____

Additional comment

The sum of angles in the triangle is 180°, so the angle at C (the angle of elevation) is the same as the angle we just figured:

∠C + 90° +66° = 180°

∠C +66° = 90° . . . . . . . subtracting 90°; shows C is complementary to 66°

∠C = 90° -66° = 24°

As a rule, the angle of elevation and the angle of depression are the same.

8 0

3 years ago

Gideon is painting all sides of a square pyramid-shaped decoration at the top of his fence post. A net of the decoration is show

frez [133]

Gideon is painting all sides thus we find the overall area of the square pyramid given in the picture. A square pyramid is a polyhedron that consists of a square and 4 triangles. To solve the area that Gideon will have to paint, we can calculate the area of the square and the area of the triangles then add these two values of area. We proceed as follows:
Area of the square = s^2 where s is the measure of the side
Area of the square = 4^2 = 16 in^2

Area of the triangle= 1/2 bh where b is the base of the triangle and h is height of the triangle
Area of the triangle = 1/2 (4) (5) = 10 in^2
We multiply the area of the triangle to four in order to obtain the total area of the triangles.
Total area of the triangles = 4 x 10 = 40 in^2

We then add the two areas,
Total Area = 16 + 40 = 56 in^2

Thus the total area that Gideon will have to paint for one square pyramid is 56 in^2.

6 0

3 years ago

Y=5x+20 Y=-7x-16 Solve each system by substitution

icang [17]

Answer:

x=3

y=35

Step-by-step explanation:

5x+20=-7x-16

-16+20=4

5x=-7x+4

5x+7x= 12x

12x=4

12/4=3

7 0

4 years ago

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