Answer:
i do not know what i would do if i was you- ppppppproooooobably have an anxiety attack ngl
Explanation:
hey, but thanks for the free points and maybe try thinking about what will happen AFTER that horrible time
so instead of thinking about all the children coughing and wiping their boogers on their sleeves-
think about what will happen after the event- like watching net flix with a floofy blanket
♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛♛
THEY ARE ALL YOURS!!!!!!!
Answer:
I would say It would be more expensive.
Explanation:
Not really sure how to put this in a complete sentence
Qhahsysyysysysysyysxyyssgsdhjjcjjcxjx
Answer:
What is 34? O A. -1 O B. -i O C. 1 O D. i
Explanation:
Answer:
Explanation:

So first, we have to plug in zero and see if we can evaluate this limit simply from that.
When we plug in zero we get: (2e^0-2)/0
e^0 is 1 so we have 2-2/0 or 0/0. So we have an indeterminate form type 0/0.
This means we have to apply L'Hospital's Rule.
As a reminder L'Hospitals Rule is 
Meaning that we take the derivative of the top and bottom function as the approach some value "c". We can do this with a 0/0 indeterminate form.
So:
The derivative of 2e^x - 2 is just 2e^x
and the derivative of x is 1
So we are left with 
Plugging in zero we see this gives us 2 as 2(e^0) = 2(1) = 2.
Hence,
= 2