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defon
3 years ago
5

What is the value of n?

Mathematics
1 answer:
Archy [21]3 years ago
7 0

the theory is ab=cd where the lines across form eachother are a and b and the other two lines are a and d

a=7

b=n+4

c=5

d=n+8

7(n+4)=5(n+8)

7n+28=5n+40

2n+28=40

2n=12

n=6

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Are the lines parallel, perpendicular, or neither?<br> 3x-y=5 y=3x+1
erica [24]

Answer:

<em>Parallel</em>

Step-by-step explanation:

To be parallel it would have to be the exact same slope, perpendicular would be the opposite...these equations have the same slope so it is <em>parallel</em>.

3x-y=5\\3x-5=y\\y=3x-5\\\\vs\\y=3x+1

3 0
3 years ago
What is the sign of -4x\cdot y\cdot 0^6−4x⋅y⋅0 6 minus, 4, x, dot, y, dot, 0, start superscript, 6, end superscript when xxx and
castortr0y [4]

Answer:

non-negative

<em></em>

Step-by-step explanation:

Given

-4x\cdot y\cdot 0^6

x , y > 0 --- Positive numbers

Required

The sign

-4x\cdot y\cdot 0^6

First, we simplify the expression

0^6 = 0

So:

-4x\cdot y\cdot 0^6 = -4x\cdot y\cdot 0

The product of 0 and any factor is 0. So:

-4x\cdot y\cdot 0^6 = 0

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4 0
3 years ago
Which one is the correct one
kenny6666 [7]

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Find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)
Murljashka [212]

Answer:

Equation of circle is: \mathbf{(x+1)^2+(y-5)^2=28.94}

Step-by-step explanation:

We need to find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)

Endpoints of a diameter A(−6, 3) and B(4, 7)

The general equation of circle is: (x-h)^2+(y-k)^2=r^2

Where r is radius and (h,k) is centre of circle.

Finding centre of circle

The midpoint of diameter is centre of circle.

So, finding midpoint of A(−6, 3) and B(4, 7)

The formula used is: Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

We have x_1=-6, y_1=3, x_2=4, y_2=7

Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\Midpoint=(\frac{-6+4}{2} ,\frac{3+7}{2} )\\Midpoint=(\frac{-2}{2} ,\frac{10}{2} )\\Midpoint=(-1 ,5)

So, we get Midpoint (x,y)=(-1,5)

Finding radius of circle

Radius of circle can be found by first finding diameter using distance formula and then divide it by 2.

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\Distance=\sqrt{(4-(-6))^2+(7-3)^2} \\Distance=\sqrt{(4+6)^2+(7-3)^2} \\Distance=\sqrt{(10)^2+(4)^2} \\Distance=\sqrt{100+16}\\Distance=\sqrt{116}\\Distance = 10.77

So, Diameter = 10.77

Radius = Diameter/2 = 5.38

Equation of circle

Equation of circle having centre(-1,5) and radius r = 5.38 is:

(x-h)^2+(y-k)^2=r^2\\(x-(-1))^2+(y-5)^2=(5.38)^2\\(x+1)^2+(y-5)^2=28.94

So, Equation of circle is: \mathbf{(x+1)^2+(y-5)^2=28.94}

4 0
3 years ago
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