Answer:
nice avatar and the answer is a
i
Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Y=-2 is a horizontal line, each point which lies on this line has the y-coordinate -2.
Only in option C both points have the y-coordinate equal to -2.
The answer is C.
rewrite -1 1/3 as a decimal: -1.5
-2.1 - x = -1.5
Subtract -2.1 From both sides:
X = -1.5 - -2.1 = -1.5 + 2.1
X = 0.6
Answer: B. 0.6
