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3 years ago

How do you simplify 2(m+5)+8(6m+1)

Mathematics

2 answers:

Sholpan [36]3 years ago

7 0

galina1969 [7]3 years ago

5 0

You must use distributive property to get 2m+10+48m+8 and then add all like terms. You get 50m+18 as your final answer.

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My teacher is making us do this but we haven’t learned it test someone please help

Leno4ka [110]

Hello from MrBillDoesMath!

Answer:

35 degrees

Discussion:

The angle shown is a right angle. That is, it contains 90 degrees. So we need to solve

90 = 7x + 11x => as 7x + 11x = 18x

90 = 18x => divide both sides by 18

x= 90/18 = 5

The measure of the smaller angle is 7x = 7(5) = 35

Thank you,

MrB

6 0

3 years ago

Please help! What is true about the graph on the interval from point c to point d?

Lelechka [254]

Your selected answer is correct

4 0

3 years ago

If you know two points on a line, how can you find the rate of change of the variables being graphed?

Dmitrij [34]

The rate of change refers to the rate at which the independent variable is changing as the dependent variable changes. You will find the independent variable on the y-axis and the dependent variable on the x-axis.
Then, pick two points.You will sub them into the equation.
$rate of change = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

5 0

4 years ago

Need Help!!! ASAP

RoseWind [281]

Answer:

$P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}$

$P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}$

$P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}$

Step-by-step explanation:

The given probabilities are:

$P(red)=\frac{2}{7}$

$P(blue)=\frac{3}{14}$

Their sum is $P(red)+P(blue)=\frac{2}{7}+\frac{3}{14}$

The probabilities that will complete the model should add up to $\frac{1}{2}$ so that the sum of all probabilities is 1.

$P(green)+P(yellow)=\frac{2}{7}+\frac{2}{7}\ne\frac{1}{2}$

$P(green)+P(yellow)=\frac{3}{8}+\frac{1}{8}=\frac{1}{2}$

$P(green)+P(yellow)=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}$

$P(green)+P(yellow)=\frac{5}{21}+\frac{11}{21}\ne\frac{1}{2}$

$P(green)+P(yellow)=\frac{3}{7}+\frac{1}{14}=\frac{1}{2}$

5 0

4 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago