Answer:x=5
2(3x-2)=6x-4
6x-4=26
6x=30
x=5
Step-by-step explanation:
Answer:
We conclude that segment QR is the shortest.
Hence, option B is true.
Step-by-step explanation:
First, we need to determine the missing angle m∠R
Given the triangle Δ∠PQR
m∠P = 48°
m∠Q = 83°
m∠R = ?
We know the sum of angles of a triangle is 180°.
m∠P+m∠Q+m∠R = 180°
48°+83°+m∠R=180°
m∠R = 180° - 48° - 83°
m∠R = 49°
Thus, the value of m∠R = 49°
We know that the longest side in a triangle is opposite the largest angle, and the shortest side is opposite the smallest angle.
Here,
m∠P = 48° is the shortest angle.
As the side QR segment is opposite the smallest angle i.e. m∠P = 48°
Therefore, we conclude that segment QR is the shortest.
Hence, option B is true.
For the first one, we know that is a right angle. right angles are 90 degrees. if we subtract 90 - 49 that equals 41. so the second value needs to equal 41. since we have a 3 there already, we are going to subtract 41-3, which is 38. x = 38
The base is 3+(x), altitude is x so substitute. Now we know the area of a triangle is base X height X 1/2. Substitute again! 1/2 (3+x)(x)=35. Multiply both sides by 2 to cancel out the 1/2. Now you have (x)(x+3)=70 and you have to foil out the left side x^2+3x=70. Subtract 70 on both sides x^2+3x-70=0. Find two numbers that multiply to -70 and add to 3. Solve (x+10)(x-7)=0. the x value is 7. since you can't have negative length values. Substitute 7 into 3+x for the base so you know the base is 10 and the height is 7.