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Llana [10]
3 years ago
11

Draw a model to represent the product 41x16

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0
The answer is I don't know because if you add them both you get 5 and 6.
You might be interested in
The length of a planet's orbit around a star is approximately 17,650,000 km.
daser333 [38]

Answer:

1150 km/hr

Step-by-step explanation:

Formula for Average Speed is given as = Distance in Kilometers/ Time in Hours

In the question we are given the following parameters.

The length of a planet's orbit around a star = Distance = 17,650,000 km.

Time taken to complete a full orbit = 640 Earth days

Step 1

We need to convert the time in days to hours

1 Earth day = 24 hours

640 Earth days =

We cross multiply

640 Earth days × 24 hours

= 15360 hours.

Step 2

Average Speed = Distance in Kilometers/ Time in Hours

Average Speed = 17,650,000 km. /15360 hours

Average Speed = 1149.0885417 km/hr

Approximately to 3 significant figures=

1150 km/hr

Therefore, the planets average speed in kmh-1 to 3sf is 1150 km/hr

8 0
3 years ago
A desk is on sale for $666 , which is 28% less than the regular price. What is the regular price?
-BARSIC- [3]
The regular price is 925
6 0
3 years ago
Read 2 more answers
Which of the following is equivalent to a real number?
Aleksandr-060686 [28]

Answer:

C) -144^¹/₃

Step-by-step explanation:

Having a number to the power of a fraction is the equivalent of rooting by its reciprocal. So, the sixth root, fourth root, cube root, and square root. Only odd roots can have negative answers (∛x, x can be negative; √y, y can not be negative unless we talk about imaginary numbers).

Since we are looking for a real number, C, showing a cube root of a negative number, must be the answer.

4 0
3 years ago
4x – y = 7 3y – 12x = –21
Elis [28]

Answer:

y= 4x − 7 or 0=0

Step-by-step explanation:

4x−y+−4x=7+−4x

6 0
2 years ago
Read 2 more answers
PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
Liula [17]

Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

7 0
3 years ago
Read 2 more answers
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