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Cloud [144]
3 years ago
5

What is 528−−√+63−−√528+63 in simplest radical form?

Mathematics
2 answers:
Montano1993 [528]3 years ago
6 0

Answer: 13\sqrt{7}

Step-by-step explanation:

In the simple radical form there are no square root is remain to find.

Since, the given expression,

5\sqrt{28} + \sqrt{63}

5\sqrt{4\times 7} + \sqrt{9\times 7}

5\sqrt{4} \times \sqrt{7} + \sqrt{9}\times \sqrt{7}

5\times 2 \times \sqrt{7} + 3\times \sqrt{7}

10 \sqrt{7} + 3\sqrt{7}

(10 + 3)\sqrt{7}

13\sqrt{7}

Since, we do not need to find further square root of 7.

Thus, the required radical form of 5\sqrt{28} + \sqrt{63} is 13\sqrt{7}.

Rufina [12.5K]3 years ago
3 0

Answer:

13\sqrt{7}

Step-by-step explanation:

5\sqrt{28} +\sqrt{63}

To simplify the given expression we simplify each radical

5\sqrt{28} = 5\sqrt{4*7} = 5*2\sqrt{7} =10\sqrt{7}

\sqrt{63} = \sqrt{9*7} =3\sqrt{7}

5\sqrt{28} +\sqrt{63}

10\sqrt{7}+3\sqrt{7}

13\sqrt{7}

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