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Liono4ka [1.6K]
3 years ago
9

Which pairs show equivalent expression

Mathematics
1 answer:
Savatey [412]3 years ago
8 0

Hey blink!!!!!!! second one is your answer

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How do you simplify this equation?
Troyanec [42]
4^3*4^-5= 4^-2 (add the exponents since the base is the same)
5^-4*5^1= 5^-3 (add the exponents since the base is the same)

Square both terms (double the exponents)
(4^-2)^2= 4^-4
(5^-3)2= 5^-6

Then take out negative exponents (x^-a= 1/x^a)
4^-4 /5^-6 = 5^6/4^4

Final answer: 5^6/4^4

If you want it in number form
5^6= 15625
4^4=256
15625/256= 61.035...
5 0
3 years ago
Explain why<br><br>1 + 2 + 3 + 4 + 5 + ... + <img src="https://tex.z-dn.net/?f=%7Binfinity%7D" id="TexFormula1" title="{infinity
Readme [11.4K]

Answer:

1+2+3+4+5+...+=1/12

Step-by-step explanation:

ANSWER IS 12

5 0
3 years ago
The following is an arithmetic series.<br> 31+33.5+36+38.5+...<br> O True<br> O False
Aleks04 [339]

9514 1404 393

Answer:

  True

Step-by-step explanation:

It is the sum of numbers having a common difference. The fact that it is a sum makes it a series (as opposed to a sequence, which is just a list of numbers). The common difference (of 2.5) makes it an arithmetic series.

True, the sum is an arithmetic series.

3 0
3 years ago
Read 2 more answers
Need help ASAP!!!
Annette [7]

Answer:

1. Identifying parts of a triangle can help you find trigonometric ratios by seeing what side and angle measurements you have and if you have enough information to solve the triangle.

2. To use inverse trigonometric functions you should have to find the unknown measure of an angle of a right triangle when two side lengths are known. So, you simply use the same math as you would in trig ratios, but in a calculator you would have to click cos^-1, tan^-1, or sin^-1.

6 0
3 years ago
"You are dating Moon rocks based on their proportions of uranium-238 (half-life of about 4.5 billion years) and its ultimate dec
Olenka [21]

Step-by-step explanation:

a.

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 41% = t

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope  = x

N = mass of the parent isotope left after the time, (t)  = 59% of x = 0.59x

t_{\frac{1}{2}} = half life of the isotope  = 4.5 billion years

\lambda = rate constant

Now put all the given values in this formula, we get

0.59x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}

t = 3.4 billion years

The age a rock is 3.4 billion years.

b.

Initial mass of the isotope = x

Time taken by the sample to decay its mass by 35%= t

Formula used :

N=N_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

N_o = initial mass of isotope  = x

N = mass of the parent isotope left after the time, (t)  = 65% of x = 0.65x

t_{\frac{1}{2}} = half life of the isotope  = 4.5 billion years

\lambda = rate constant

Now put all the given values in this formula, we get

0.65x=x\times e^{-(\frac{0.693}{\text{4.5 billion years}})\times t}

t = 2.8 billion years

The age a rock is 2.8 billion years.

5 0
4 years ago
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