What is the factored form of n2 – 25?

Mathematics

1 answer:

lesantik [10]3 years ago

3 0

Answer: (n + 5)(n - 5)

Explanation: In this problem, we have a binomial that's the difference of two squares because n² and 25 are both perfect squares and we are subtracting or taking the difference of these two squares.

Since the difference of two squares factors as the product of two binomials, we can setup our parenthses and in the first position, we use the factors of n² that are the same which are n · n.

In the second position, we use +5 and -5 as our factors of -25.

So our answer is (n + 5)(n - 5).

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Can someone please help me??

aivan3 [116]

Answer:

-16 is the answer after evaluating

Step-by-step explanation:

${b }^{2} - 7b - 6 \\ 5 { }^{2} - 7 \times 5 -6 \\ 25 - 35 - 6 \\ 25 - 41 \\ - 16$

4 0

2 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$