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Reil [10]
3 years ago
14

a box shaped biscuits contain 15 squares, 17 triangles, 6 rectangles, 4 diamonds and 8 hexagons. If a biscuit is chosen at rando

m, what is the probability of choosing a square one (give your answer as a fraction in simplest form
Mathematics
1 answer:
Triss [41]3 years ago
3 0
Add the numbers up to get the total number of biscuits, which will be 50. Then, make a fraction using the squares, which will be 15/50. Simplify by 5. The answer will be 3/10. 
I hope this helped!
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alexira [117]

by the use of elimination method

make all coefficients of subject to be eliminated similar..by multiplying the coefficients with one another

for eqn(i)

5(-10y+9x=-9)

-50y+45x=-45

for eqn(ii)

9(10y+5x=-5)

90y+45x=-45

-50y+45x=-45

90y+45x=-45

...subtract each set from the other...

we get

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from eqn(i)

10y+5x=-5

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3 years ago
Write and equivalent exspression to 8k-(5+2k) without parentheses then simplify
Nezavi [6.7K]

Answer:

6k - 5

Step-by-step explanation:

8k-(5+2k)

8k -5 -2k

6k - 5

3 0
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Semmy [17]

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find the value of x of given figure and solve this question step by step plzz help question number D​​
Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm

Applying Pythagoras theorem:

(Hypotenuse)^2  = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm

Solving for triangle ABC

Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\

Applying Pythagoras theorem

AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm

Hence,

x=15 cm

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2 years ago
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