Answer:
Step-by-step explanation:
Let us assume that if possible in the group of 101, each had a different number of friends. Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.
Say P has 100 friends then P has all other persons as friends. In this case, there cannot be any one who has 0 friend. So a contradiction. Hence proved
Part ii: EVen if instead of 101, say n people are there same proof follows as
if different number of friends then they would be 0,1,2...n-1
If one person has n-1 friends then there cannot be any one who does not have any friend.
Thus same proof follows.
Answer: 
Step-by-step explanation:
multiply these -3/7 times by 3/8: Answer is -9/56
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Answer:
A) The numerator is 10.
B)The numerator is 18.
C)The numerator is 8.
D)The numerator is 16.
Step-by-step explanation:
A) 
The numerator ,a = 10.
B) 
The numerator, b = 18.
C) 
The numerator ,c = 8.
D)
The numerator,d = 16.
Answer:
by vertically opposite angle theorem
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Answer:
1
Step-by-step explanation:
