Answer:
49/250 I think I'm not sure though
Let x be the mass of the paperbacks and y be the mass of the textbook.
20x + 9y = 44.4 ----------- (1)
25x + 10y = 51 -------------(2)
(1) x 10:
200x + 90y = 444 --------(1a)
(2) x 9:
225x + 90y = 459 --------(2a)
(2a) - (1a):
25x = 15
x = 0.6 -------- sub into (1)
20 (0.6) + 9y = 44.4
12 + 9y = 44.4
9y = 44.4 - 12
9y = 32.4
y = 3.6
So the paperback's mass is 0.6 pounds and textbook is 3.6 pounds
Let’s use y as a replacement for a number. You would do 3y-7 since you multiply by three and take away seven.
Answer:
-35
___
27
Step-by-step explanation:
Start by setting up your pairs (x,y)
-5 & 7 are x
3 & 9 are y
X * X
---------- ÷
Y * Y
(-5, 7)
---------
(3, 9)
-35
-------
27
Answer:
5
Step-by-step explanation:
