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statuscvo [17]
3 years ago
7

Given ln(y-4)=2t, solve for y

Mathematics
1 answer:
Julli [10]3 years ago
5 0
The answer to this problem is Y=2t+4
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Angles that share a vertex, but not a side are called
djyliett [7]
Adjacent angles-
  2 angles that share a common vertex, a common side and no common interior points.

The answer is ADJACENT ANGLE

7 0
3 years ago
Can you help me with these 3?
miskamm [114]

Step-by-step explanation:

1. 5,11,17,23,29,35

Common difference is 6

3. 8,21,34, 47,60

Common difference is 13

5. 5,10,15,20,25

Common difference is 5

3 0
3 years ago
In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

\mu = 521 \sigma = \sqrt{10201} = 101

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0
3 years ago
In the diagram AB=AD and
hammer [34]

Answer:

AC ≅ AE

Step-by-step explanation:

According to the SAS congruence theorem, if two triangles have 2 corresponding sides that are equal, and also have one included corresponding angle that are equal to each other in both triangles, both triangles are regarded as congruent.

Given ∆ABC and ∆ADC in the question above, we are told that segment AB ≅ AD, and also <BAC ≅ <DAC, the additional information that is necessary to prove that ∆ABC and ∆ADC are congruent, according to the SAS theorem, is segment AC ≅ segment AE.

This will satisfy the requirements of the SAS theorem for considering 2 triangles to be equal or congruent.

6 0
3 years ago
A piece of paper is randomly selected from a stack that contains 15 small, 44 large, and 20 extra large pieces.
Gre4nikov [31]
C.

(A=wrong | 44/79=.557)
(B=wrong | 15/79=.19)
(C=correct | 20/79=.253)
6 0
3 years ago
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