Given ln(y-4)=2t, solve for y

Second to last question, Find I 50 points

ahrayia [7]

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from angle I, we know the opposite side and the hypotenuse. Therefore, we should use sine.

sin(I) = $\frac{\sqrt{39}}{\sqrt{51}}$

To solve, you can use your calculator and the inverse sine function (sin^-1).

I = sin^-1( $\frac{\sqrt{39}}{\sqrt{51}}$ )

I = 61 degrees

Hope this helps!

5 0

3 years ago

Read 2 more answers

janie has four pieces of fruit two of the pieces of fruit are bananas write two fractions that describe the fraction of fruit th

-BARSIC- [3]

Answer:

1/2, 2/4.

Step-by-step explanation:

2/4 is one fraction because there are 2 bananas out of 4 pieces of fruit.

This can be simplified to 1/2.

3 0

3 years ago

The chances of winning are often written in terms of odds rather than probabilities. The odds of winning is the ratio of the num

Free_Kalibri [48]

Answer:

you should play the game with the probability of winning is one tenth

Step-by-step explanation:

If the probability of winning an instant prize game is one tenth, then the odds in the game can be described as 1:9 . The odds are clearly better than the game with odds 1:10.

In other words,

If the odds of winning a instant prize game are 1:10, then the probability of winning the game is one eleventh. This is a lower probability than the game which has the probability of winning one tenth.

3 0

3 years ago

Instructions: Match each equations with correct type of event.

Mazyrski [523]

The question is incomplete. Below you will find the missing contents.

The correct match of events with order are,

P(A)P(B|A) - Dependent event
P(A)+P(B) - Mutually exclusive events
P(A and B)/P(A) - Conditional events
P(A) . P(B) - Independent Events
P(A)+P(B) -P(A and B) - not Mutually exclusive events.

When two events A and B are independent then,

P(A and B)=P(A).P(B)

when A and B are dependent events then,

P(A and B) = P(A) . P(B|A)

When two events A and B are mutually exclusive events then,

P(A and B)=0

So, P(A or B) = P(A) + P(B) - P(A and B) = P(A) + P(B)

P(A) + P(B) = P(A or B)

When events are not mutually exclusive then the general relation is,

P(A or B) = P(A) + P(B) - P(A and B)

If the probability of the event B conditioned by A is given by,

$\mathrm{P(B|A)=\frac{P(A~and~B)}{P(A)}}$

Hence the correct match are -

$\mathrm{P(A)P(B|A)\rightarrow}$ Dependent event
$\mathrm{P(A)+P(B)}\rightarrow$ Mutually exclusive events
$\mathrm{\frac{P(A ~and ~B)}{P(A)}\rightarrow}$ Conditional events
$\mathrm{P(A) . P(B)\rightarrow}$ Independent Events
$\mathrm{P(A)+P(B) -P(A ~and ~B)\rightarrow}$ not Mutually exclusive events.

Learn more about Probability of Events here -

brainly.com/question/79654680

#SPJ10

5 0

2 years ago

When a researcher asks respondents for the names or identities of others like themselves who might qualify to take part in the s

DanielleElmas [232]

Answer:

Chain referral sampling

Step-by-step explanation:

Chain referral sampling is also known as snowball sampling. In this form of sampling, the samples are collected from the referrals given by the existing samples. The samples are collected and the research is conducted respectively. This method is used in the business marketing also. The places where the people are not known by the company, the method of chain referrals are made and the samples are collected.

5 0

3 years ago