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statuscvo [17]
3 years ago
7

Given ln(y-4)=2t, solve for y

Mathematics
1 answer:
Julli [10]3 years ago
5 0
The answer to this problem is Y=2t+4
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How to figure out answer ?
spin [16.1K]
\sin 45=\dfrac{y}{11\sqrt6}\\
\dfrac{\sqrt2}{2}=\dfrac{y}{11\sqrt6}\\
2y=11\sqrt{12}\\
y=\dfrac{11\sqrt{12}}{2}\\\\
\tan 60=\dfrac{x}{y}\\
\tan 60=\dfrac{x}{\dfrac{11\sqrt{12}}{2}}\\
\sqrt3=\dfrac{2x}{11\sqrt{12}}\\
2x=11\sqrt{36}\\
2x=66\\
x=33 \Rightarrow D


7 0
2 years ago
How much $ do you make in an hour if you earn $42.25 in 6.5 hours?
mafiozo [28]
$6.50 per hour. 42.25/6.5=6.5
7 0
3 years ago
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
Im need help on this question
dimulka [17.4K]
You were right, its the second choice CA=CB+BA
4 0
2 years ago
Explain how you can tell whether the sum of two integers is positive or negative, before adding them.
julsineya [31]

Answer:

The sum of any integer and its opposite is equal to zero. adding two negative integers always yields a negative sum. To find the sum of a positive and a negative integer, take the absolute value of each integer and then subtract these values.

7 0
3 years ago
Read 2 more answers
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