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Nonamiya [84]
3 years ago
11

Can someone plz help plzzzzz

Mathematics
1 answer:
pshichka [43]3 years ago
4 0
I’m not gonna answer the entire thing for you but I’ll give you a Headstart. In problems like Number nine you take where the Second leg is an subtracted by the first leg giving you the degree measure. And problems like 18 through 21 you have to find angle measures with the same markings
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iragen [17]
TW = 32

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4 years ago
Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

5 0
3 years ago
The total number of subsets of {A, B, C} is _____.. . . a.6. b.7. c.8
Triss [41]
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5 0
4 years ago
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What are the values of the trigonometric ratios for this triangle?
Norma-Jean [14]
We know that
in the right triangle

<span>sinθ=opposite side/hypotenuse
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adjacent side angle <span>θ=15
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Please help for brainliest.
Kaylis [27]

Answer:

its C

Step-by-step explanation:

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