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Wittaler [7]
4 years ago
12

Find the perimeter of a regular pentagon with sides of (3x + 5).

Mathematics
1 answer:
kotegsom [21]4 years ago
4 0

Answer:

  5(3x + 5)   or   15x + 25

Step-by-step explanation:

A regular pentagon has 5 sides of equal length. The perimeter is the sum of the lengths of those sides. We can use multiplication to find the sum of 5 of the same value:

  P = 5(3x +5)

Perhaps you want it expanded. Using the distributive property, we multiply each term in parentheses by 5:

  P = 15x + 25

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0\underbrace{.000000004}_{9\to}72=4.72\cdot10^{-9}
5 0
3 years ago
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Given: ABCD is a trapezoid, AB=CD, MN is a midsegment, MN=30, BC=17, AB=26 Find: m∠A, m∠B, m∠C, and m∠D
enyata [817]

Answer:

The measures of angle ∠A, ∠B, ∠C, and ∠D are 60, 120, 120 and 60 degree respectively.

Step-by-step explanation:

Given information:AB=CD, MN is a midsegment, MN=30, BC=17, AB=26

Since two opposites sides are equal, therefore we can say that two no parallel sides are equal.

The length of midsegment is average of length of parallel lines.

MN=\frac{AD+BC}{2}

30=\frac{AD+17}{2}

60=AD+17

43=AD

Draw perpendiculars on AD from B and C. Let angle A be θ. D

AD=AE+EF+FD

Since ABCD is an isosceles trapezoid, therefore AE=FD and EF=BC

AD=AE+EF+AE

43=2(AE)+17

26=2(AE)

13=AE

\cos\theta=\frac{base}{hypotenuse}

\cos\theta=\frac{AE}{AB}

\cos\theta=\frac{13}{26}

\cos\theta=\frac{1}{2}

\theta=\cos^{-1}\frac{1}{2}

\theta=60

Since ABCD is an isosceles trapezoid, therefore angles A and D are same. Angle B and C are same.

\angle A=\angle D=60^{\circ}

The sum of two consecutive angles of a trapezoid is 180 degree by consecutive interior angle theorem.

\angle A+\angle B=180^{\circ}

60^{\circ}+\angle B=180^{\circ}

\angle B=120^{\circ}

\angle B=\angle C=120^{\circ}

Therefore measures of angle ∠A, ∠B, ∠C, and ∠D are 60, 120, 120 and 60 degree respectively.

3 0
4 years ago
PLEASE HELP I WILL DO ANYTHING IN THE WORLD
Inessa05 [86]
7) 26 (M<a = M<C)
8)59

4 0
4 years ago
Courtney walked from her house to the beach at a constant speed of 4 kilometers per hour, and then walked
RUDIKE [14]

<em><u>The system of equations that represents this situation are:</u></em>

q + p = 2

4q + 5p = 8

<em><u>Solution:</u></em>

Let  q be the number of hours it took Courtney to walk from her house to the beach

Let p be the number of hours it took her to walk from the beach to the park

<em><u>The entire walk took 2 hours</u></em>

Therefore,

q + p = 2 ------- eqn 1

<em><u>The  total distance Courtney walked was 8 kilometers</u></em>

Total distance = 8 km

Courtney walked from her house to the beach at a constant speed of 4 kilometers per hour

Then walked  from the beach to the park at a constant speed of 5 kilometers per hour

<em><u>Distance is given as:</u></em>

distance = speed \times time

<em><u>From her house to the beach:</u></em>

distance = 4 \times q = 4q

<em><u>From the beach to the park:</u></em>

distance = 5 \times p = 5p

We know that,

Total distance = 8 km

Therefore,

4q + 5p = 8 ------ eqn 2

<em><u>Thus the system of equations that represents this situation are:</u></em>

q + p = 2

4q + 5p = 8

8 0
4 years ago
.
yan [13]

Answer:i dfont kngodw

Step-by-step explanation:

its probably c

3 0
4 years ago
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