2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
Yes, it would be what you have written
Answer:
12x + 2
Step-by-step explanation:
12 is multiplyed by both the x and the (1/6) since it is outside the equation.
so 12 times x = 12x since we dont know what x is
and 12 times (1/6) = (12/6) = 2
Answer and Step-by-step explanation:
Simply use the Pythagorean Theorem to solve.
The Pythagorean Theorem is used to solve for a side in right triangles.

<u>Plug the sides values into the equation.</u>
<- This is the answer.
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