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2 years ago

Please help, I will mark brainiest answer!

Mathematics

1 answer:

weqwewe [10]2 years ago

3 0

Answer:

x = 5

Step-by-step explanation:

It is given that the angle below is a right angle, meaning that it is 90 degrees.

So, 8x and 50 must both add up to 90 degrees.

Let's make an equation that we can solve using this information.

8x + 50 = 90

8x = 40

x = 5

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Find the distance between this pair of points (-3,5) and (5. - 1)

padilas [110]

Answer:

14.

Step-by-step explanation:

6 down, 8 right

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3 years ago

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Which table represents of a linear function?

xz_007 [3.2K]

Answer:

X | Y

2 | 7

4 | 9 <-- linear.

6 | 11

8 | 13

A linear function is when there is an even consonant decline or up-rise.

X | Y

1 | 2

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3 | 6

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2 years ago

I need to divide this equation:

Luba_88 [7]

1+7/11 = 11/11+7/11 = 18/11 2+1/2 = 4/2+1/2 = 5/2 (18/11)/(5/2) = (18/11)*(2/5) = 36/55

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3 years ago

A grocery store sells a bag of 3 oranges for $2.01. What is the cost of oranges, in dollars per orange?

Alik [6]

Answer:

0.67

Step-by-step explanation:

2.01 is the total for three oranges.

the math would be 2.01 ÷ 3 = 0.67

to check your answer:

if one orange equals 0.67 and you have three of them

the math would be 3 × 0.67 = 2.01

3 0

2 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago