Answer:
The speed on motorboat is 20 mph
Step-by-step explanation:
here, we want to find the speed on the motorboat
if he has a speed of x mph on the motor boat, his speed on the ski will be (x + 10) mph
The total hours is 4 hours
Mathematically; speed = distance/time
Time on ski is 27/x+ 10
Time on motor boat is 62/x
The addition of both is 4
Thus;
27/(x + 10) + 62/x = 4
27(x) + 62(x + 10) = 4(x)(x + 10)
27x + 62x + 620 = 4(x^2 + 10x)
89x + 620 = 4x^2 + 40x
4x^2 -49x-620 = 0
using the quadratic formula;
{-b ± √(b^2-4ac)}/2a
where a = 4, b = -49 and c = -620
= 49 ± √(-49)^2-4(4)(-620)/8
So we have
49+ 111/8 or 49-111/8
Speed cannot be negative
(49 + 111)/8
= 20 mph
Answer:
3/10
Step-by-step explanation:
2/5 + x = 7/10
x = 7/10 - 2/5
x = 7/10 - 4/10
x = 3/10
2x=y
two times the number of minutes = the amount of pages
(0,0)(1,3) = (3 - 0) / (1 - 0) = 3
slope = 3
equation for this line is y = 3x...and since u have (0,0) as a point on this line, ur y int is (0,0)
g(x) = 7x + 2...slope here is 7 and y int is (0,2)
==========================
The slope of f(x) = 3. I found this using the slope formula (y2 - y1) / (x2 - x1).
The slope of g(x) = 7. Because in y = mx + b form, the slope is in the m position.
g(x) has a steeper slope.
=========================
f(x) has a y int of (0,0)...the line cuts thru the origin.
g(x) has a y int of (0,2)...because in y = mx + b form, the y int will be in the b position.
So, g(x) has a greater y int.
Cross multiply:
30n = 2400. Then n = 80.
