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Vlad [161]
3 years ago
9

Can someone help me i'm really lost

Mathematics
2 answers:
aniked [119]3 years ago
8 0
1,100m=850m+2000

First, subtract 850m from both sides.

1,100-850=250

250m=2000

Divide each side by 250

m=8

It will be 8 months when they paid the same amount.

1100(8)=8,800

Shaun paid 8,800 dollars

850(8)=6,800
6800+2000=8,800
Taliyah paid 8,800 dollars

8,800+8,800=17,600

They spent 17,600 together.

A) 8 months
B) 17,600 dollars
rusak2 [61]3 years ago
4 0
Its asking how much did they both spent, in total, in order to reach the same amount spent in part A
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The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
I need help quick!Please help me!
mina [271]

Oh shucks, that's crazy man

6 0
3 years ago
Brainly admin please don't delete this i actually forgot what is 1x0 1x2 and 0x2
Serga [27]

first one is 0 second one is 2 and then the last one is 0

7 0
2 years ago
Read 2 more answers
You buy Apple stock for $120 per share over a period of time the stock value increased at a weekly rate of 5% you sell the stock
Rainbow [258]

Answer:

8.31  weeks

Step-by-step explanation:

Given that the cost of one share of Apple stock, C=$120

Rate is the increment of the stock value, R= 5%/week=0.05 / week.

Assuming that after t week, the stock has been sold for $180.

Since the stock value increased at 5% every week, so, the interest is compounded weekly, so

S=C\left(1+R\right)^t \\\\ \Rightarrow 180 = 120\left(1+0.05\right)^t \\\\  \Rightarrow 180 = 120\left(1.05 )^t \\\\

\Rightarrow \frac{180}{120}=1.05^t \\\\\Rightarrow 1.5=1.05^t

\Rightarrow \ln(1.5)=t \ln(1.05) [taking log both sides]

\Rightarrow t=\frac {\ln(1.5)}{\ln(1.05)}=8.31 weeks

Hence, after 8.31  weeks the stock has been sold for $180.

6 0
3 years ago
Find LM while showing work.
Contact [7]
X + 0.5 + 3x - 2 = 3x + 1.5
X= 3.5
Putting the all x on the right side and distributing all the numbers on the left side
8 0
3 years ago
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