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3 years ago

What is -3y-y equal to

Mathematics

2 answers:

alukav5142 [94]3 years ago

8 0

-4y is correct, you cant for get about the - or y

pav-90 [236]3 years ago

7 0

Im pretty sure its -4 soz if im wrong

best of luck (:

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3) Scenario 1 Scenario 2 y = 50x x is time in hours y is distance in miles Compare the scenarios and determine which shows the g

Olegator [25]

Answer:

Option A.

Step-by-step explanation:

Consider the below figure attached with this question.

Scenario 1 represented by the graph.

From the graph it is clear that the line passes through the points (1,60) and (2,120).

Slope of the line is

$y=\dfrac{y_2-y_1}{x_2-x_1}$

$y=\dfrac{120-60}{2-1}=60$

The slope of line is 60. It means the speed is 60 miles per hour.

Scenario 2 defined by the equation,

$y=50x$

If an equation defined as $y=mx+b$ , then m is slope and b is y-intercept.

$m=50$

The slope of line is 50. It means the speed is 50 miles per hour.

The slope of Scenario 1 is greater than slope of Scenario 2. So, the Scenario 1 shows the greater speed.

Hence, the correct option is A.

6 0

3 years ago

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A square is always a parallelogram. True False

agasfer [191]

Answer:

yes,

Step-by-step explanation:

because of them being quadrilaterals

8 0

4 years ago

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If y varies with x, and y=-20 and x=5, what is x when y=-30?

vladimir1956 [14]

If y = -30, then x = 7.5

Hope this helps.

3 0

3 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

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3 years ago

I NEED YOUR HELPP !!!

Paladinen [302]

Answer:7 4ts

Step-by-step explanation:

6 0

3 years ago

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