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Vedmedyk [2.9K]
3 years ago
12

How to use algebra tiles to show 4(2x+1)=8x+4

Mathematics
1 answer:
eimsori [14]3 years ago
5 0
Here is the answer 4
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Brainlist if right no lnks
zloy xaker [14]

Answer:∠1 and ∠5

Step-by-step explanation:

(A) ∠3 and ∠6  forms the interior angles on the same side of the transversal. Thus, this option is incorrect.

(B) ∠1 and ∠4 forms the linear pair on the straight line a, thus this option is incorrect.

(C) ∠1 and ∠5 forms the corresponding angle pair, thus this option is correct.

(D) ∠6 and ∠7 forms the linear pair on the straight line a, thus this option is incorrect.

5 0
3 years ago
Will give crown will post one more
zubka84 [21]

Answer:

1 is 22; 2 is 19; 3 is 16; 4 is 13; 5 is 10

Step-by-step explanation:

Give me that crown again

6 0
3 years ago
Read 2 more answers
2 right triangles have identical angle measures but different side lengths. The first triangle has side lengths of 6, 10, 8 and
lisabon 2012 [21]

Answer:

Dilation

Step-by-step explanation:

Given: The first triangle has side lengths of 6, 10, 8 and the second triangle has side lengths of 3, 5, 4 such that these two right triangles have identical angle measures but different side lengths.

To choose: the correct option

Dilation refers to a transformation when a figure is reduced or enlarged.

Each side of the large triangle is halved to get the small triangle.

So, Dilation transformation maps the large triangle onto the small triangle

3 0
3 years ago
Order these numbers from least to greatest. <br><br>5 10/11 <br>117/20 <br>5.84 <br>5.822​
Sliva [168]
Least to greatest: 5 10/11 , 5.822 , 5.84, 117/20.
8 0
3 years ago
Solve 3x2 + 4x = −5.
Alla [95]
Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula

for an equation in the form
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

a=3
b=4
c=5

x=\frac{-4+/- \sqrt{4^2-4(3)(5)} }{2(3)}
x=\frac{-4+/- \sqrt{16-60} }{6}
x=\frac{-4+/- \sqrt{-44} }{6}
x=\frac{-4+/- 2\sqrt{-11} }{6}
remember that√-1=i
x=\frac{-4+/- 2i\sqrt{-11} }{6}
x=\frac{-2+/- i\sqrt{-11} }{3}

x=\frac{-2+ i\sqrt{-11} }{3} or x=\frac{-2- i\sqrt{-11} }{3}


4 0
3 years ago
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