Answer:
the blue one is true
Step-by-step explanation:
Rmember (a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)this is just alot of busy work
find f+g first then find f-g
f+g=(x-4)/(x+9)+(x-9)/(x+4)
make denomenator the same
multiply left one by (x+4)/(x+4) and right one by (x+9)/(x+9)
[(x-4)(x+4)]/[(x+9)(x+4)]+[(x-9)(x+9)]/[(x+9)(x+4)]
[x²-16]/[(x+9)(x+4)]+[x²-81]/[(x+9)(x+4)]
[x²+x²-16-81]/[(x+9)(x+4)]
[2x²-97]/[(x+9)(x+4)]
now f-g
[x²-16]/[(x+9)(x+4)]-[x²-81]/[(x+9)(x+4)]
[x²-x²-16+81]/[(x+9)(x+4)]
[65]/[(x+9)(x+4)]
now we got

invert and multiply


2nd option
-7, -4/5, 0, 1/2, 7/8, and 2
Answer:
b) One sample z-test for means
Step-by-step explanation:
Normal Distribution
we have μ₀ (population mean from previous studies)
sample size n = 100
standar deviation of population σ = 0.75
And it was determined from sample, that μ = 5 : so we want to know if, at some significance level that value (which is smaller than population mean ) could help in relation to decide about rejecting hypothesis H₀
We should use a z one tail-test for means (left tail)
For this case, the first thing you should know is that the opposite sides of the parallelogram are the same.
Therefore, we have the following equations:

From equation 1 we have:


From equation 2 we have:


Answer:
the value of the variables are:
