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tensa zangetsu [6.8K]
3 years ago
13

A line segment has endpoints at (-4,-1) and (2,4). What are the coordinates of the midpoint of this line segment? A. (-1.5,2) B.

(-1,1.5) C. (0, 2.2) or D. (0.8,3)
Mathematics
2 answers:
Natalka [10]3 years ago
7 0

Answer:

B (-1, 1.5)

Step-by-step explanation:

Add the x coordinates together and divide by 2: (-4 + 2) = -2/2 = -1.

The only option with (-1)  as an x-coordinate is B, and that is the answer.

romanna [79]3 years ago
7 0

Answer:

B. (-1, 1.5)

Step-by-step explanation:

1. Add both "x" coordinates, divide by 2.

-4+2= -2/2 = -1 -> x= -1

2. Add both "y" coordinates, divide by 2.

-1+4= 3/2 = 1.5  -> y= 1.5

(x, y) -> (-1, 1.5)

Hope this helped :)

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Answer:

An equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:

  • y=-6x+7

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the equation

6x+y=6

Writing in the slope-intercept form of the line equation

y = -6x + 6

comparing with the slope-intercept form of the line equation

y = mx+b

Thus, the slope of line = m = -6

We know that the parallel lines have the same slopes.

Thus, the slope of the parallel line is also -6.

As the line passes through the point (2,−5).

Thus, using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope and (x₁, x₂) is the point

substituting the values m = -6 and the point (2,−5)

y-y_1=m\left(x-x_1\right)

y - (-5) = -6 (x - 2)

y+5=-6\left(x-2\right)

subtract 5 from both sides

y+5-5=-6\left(x-2\right)-5

y=-6x+7

Therefore, an equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:

  • y=-6x+7
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