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Arada [10]
3 years ago
11

Show work please thank you

Mathematics
1 answer:
kaheart [24]3 years ago
7 0
The easiest way to solve this is to divide the shape into 2 rectangles.

The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5

So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)

And for the smaller one it is a little bit trickier.

So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle

At the top we see that it says 6ft

We can do 10-6 to find the missing measurement.

Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10

So 10-6 = 4

Which means the number we need is 4

So now we have 5 x 4 = 20

72 + 20 = 92

Answer: 92

I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!

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Read 2 more answers
One endpoint (-1,-5) Midpoint (2,3)
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4 0
3 years ago
Equation álgebra<br> 3x^2 = 12<br> a. +3<br> b. +2<br> C. +3.5<br> d. +1.5
Tom [10]

Answer:

x=-2,2

Step-by-step explanation:

Since this is a quadratic equation, -2 or 2 could be the possible answer

Steps

$3x^2=12$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3x^2}{3}=\frac{12}{3}$

$\mathrm{Simplify}$

$x^2=4$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}$

$x=\sqrt{4},\:x=-\sqrt{4}$

Show Steps

$\sqrt{4}=2$

Show Steps

$-\sqrt{4}=-2$

$x=2,\:x=-2$

3 0
4 years ago
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