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Arada [10]
3 years ago
11

Show work please thank you

Mathematics
1 answer:
kaheart [24]3 years ago
7 0
The easiest way to solve this is to divide the shape into 2 rectangles.

The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5

So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)

And for the smaller one it is a little bit trickier.

So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle

At the top we see that it says 6ft

We can do 10-6 to find the missing measurement.

Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10

So 10-6 = 4

Which means the number we need is 4

So now we have 5 x 4 = 20

72 + 20 = 92

Answer: 92

I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!

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Solve x2 + 14x + 17 = –96 for x
jarptica [38.1K]

For this case we have to:

Given the quadratic equation of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

If we have: x ^ 2 + 14x + 17 = -96

We can rewrite it in the following way:

x ^ 2 + 14x + 17 + 96 = 0\\x ^ 2 + 14x + 113 = 0

Where:

a = 1\\b = 14\\c = 113

Where we have:

x = \frac {-14 \pm \sqrt {(14) ^ 2-4 (1) (113)}} {2 (1)}

x = \frac {-14 \pm \sqrt {(196-452)}} {2}

x = \frac {-14 \pm \sqrt {-256}} {2}

By definition: \sqrt {-1} = i

x = \frac {-14 \pm \sqrt {256} i} {2}

x = \frac {-14 \pm16i} {2}

x = \frac {-14} {2} \pm \frac {16i} {2}

x = -7 \pm8i

Thus, the roots are given by imaginary numbers:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i

Answer:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i


5 0
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