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Arada [10]
3 years ago
11

Show work please thank you

Mathematics
1 answer:
kaheart [24]3 years ago
7 0
The easiest way to solve this is to divide the shape into 2 rectangles.

The first rectangle being the big one on the left with the 12 and 6
and the second one being the little one on the right, next to it with the 5

So 12 x 6 = 72 (dont pay attention to the 7, 5, or 10, because all we need is 1 length and 1 width)

And for the smaller one it is a little bit trickier.

So on the bottom we see that is says 10ft, but we cant use that because what we really need is the measurement between the 5 and 7 on the top of the little rectangle

At the top we see that it says 6ft

We can do 10-6 to find the missing measurement.

Because the length of the whole like is 10, and the length of one of the little lines is 6, so the length of 6 + some number =10

So 10-6 = 4

Which means the number we need is 4

So now we have 5 x 4 = 20

72 + 20 = 92

Answer: 92

I also attatched an image, I hope this helps! Ask me if you have any other questions about this problem!

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Vikki [24]

Answer:

The equation is: 120 - 4x = 92. There are 7  incorrect answers.

Step-by-step explanation:

5 0
3 years ago
What is the slope of a line parallel to the line whose equation is 5x + 3y = 15
kifflom [539]
For two lines to be parallel, they must have the same slope...

3y=-5x+15

y=-5x/3 +5, y=mx+b, where m=slope so:

A parallel line with have a slope of -5/3
7 0
3 years ago
6+(-9)= I want a answer<br>​
choli [55]
It would be -3. since they’re different signs you would subtract instead of doing addition. you also would us the greater numbers sign, which, in this case, -9 is the greater number so the answers sign would be negative.
3 0
3 years ago
Read 2 more answers
ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x
fomenos

Answer:

A) x = 20

Step-by-step explanation:

ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.

Since, diagonals of a rhombus are perpendicular bisector.

\therefore \: m \angle AED = 90 \degree \\  \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90  \\ \therefore \: 5x  = 90 + 10  \\ \therefore \: 5x  = 100  \\ \\  \therefore \: x  = \frac{100}{5}  \\  \\ \huge \red{ \boxed{ \therefore \: x  =20}}

5 0
3 years ago
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
3 years ago
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