cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)
So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.
Recall that
cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)
so that
sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)
sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)
Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :
sin(<em>θ</em>) = 1 / √((-2)² + 1)
sin(<em>θ</em>) = 1/√(5)
Answer:
Length 37 cm, width 25 cm.
Step-by-step explanation:
Let the original dimensions be length x and width x - 12 cms.
The new dimensions will be length (x - 2) and width (x - 12 - 2) = x-14 cm.
So , from the areas, we have:
x(x - 12) - (x - 2)(x - 14) = 120
x^2 - 12x - (x^2 - 16x + 28) = 120
-12x + 16x - 28 = 120
4x = 148
x = 37 cms
So the length was 37 cm and the width was 37-12 = 25 cm.
I think it is (5, -4)... not completely sure though
Step-by-step explanation:
<u>Given equation:</u>
a. write a second equation so that (1,3) is the only solution of the system
To have only one solution the equation must have a different slope.
<u>Let it be 10, then the y-intercept of y = 10x + b is:</u>
<u>And the equation:</u>
b. Write a second equation so that the system has infinitely many solutions
<u>To have infinitely many solutions, both equations must be same:</u>
c. Write a second equation so that the system has no solutions.
<u>To have no solutions, the equations must have same slope but different y-intercepts:</u>
