(2,000,000) + (400,000) + (80,000) + (4,000) + (100) + (60) + (3) = 2,484,163
Let us compute first the probability of ending up an odd number when rolling a dice. A dice has faces with numbers 1 up to 6. The odd numbers within that is 3 (1, 3 and 5). Therefore, each dice has a probability of 3/6 or 1/2. Then, you use the repeated trials formula:
Probability = n!/r!(n-r)! * p^r * q^(n-r), where n is the number of tries (n=6), r is the number tries where you get an even number (r=0), p is the probability of having an even face and q is the probability of having an odd face.
Probability = 6!/0!(6!) * (1/2)^0 * (1/2)^6
Probability = 1/64
Therefore, the probability is 1/64 or 1.56%.
Heyyyyyy new friends and I have no clue what the answer is cause I don’t feel like reading that but anyway yea nfs?
Answer:
it is -30
Step-by-step explanation:
you would divide both sides by x,then f=2
using PEMDAS we come to -30
8/10 is equivalent to 4/5. just divide both 8 and 10 by 2
