Geometry questions

1 answer:

5 0

1. False. The absolute value of a number must always take the positive sign.
2. False. The Ruler Postulate only states that the numbers on the number line must be real numbers. That means, not only integers, but fractions are included as well.
3. False. The absolute value should be +0.75.

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PLEASE HELP!! I WILL MARK THE FIRST CORRECT ANSWER BRAINLIEST!!))What is the volume of this cylinder?

Aleksandr-060686 [28]

Answer:

V = 6079.04 ft³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

V = πr²h ( r is the radius and h the height )

Here diameter = 22 , then r = 22 ÷ 2 = 11 and h = 16 , then

V = 3.14 × 11² × 16

= 3.14 × 121 × 16

≈ 6079.04 ft³ ( to the nearest hundredth )

6 0

2 years ago

The mean of 10 values is 19. If further 5 values are

Leokris [45]

Answer:

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300

Now let's look at the first 10: We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

k+l+m+n+o=300-190

k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0

3 years ago

The length of a rectangle is 3131 inches greatergreater than twice the width. if the diagonal is 2 inches more than the length,

Gala2k [10]

We have a rectangle with a diagonal included. That means we have to use Pythagorean's Theorem to find the missing dimensions. We start with the width as w. The length is 31 more than twice the width, so the length is 2w+31. The hypotenuse (diagonal) is 2 more than the length, so the diagonal measures 2w+33. In a right triangle, the hypotenuse is always the longest side, so we set up Pythagorean's Theorem using the bolded values as such: $(2w+33)^2=w^2+(2w+31)^2$ . Distributing by multiplying we simplify to $4w^2+132w+1089=w^2+4w^2+124w+961$ . We need to solve for w. Once we do that we can use that value to find the length. What's nice is that the 4w^2 terms cancel each other out. So when we combine like terms and get them all on one side of the equals sign to factor we have $w^2-8w-128=0$ . The 2 numbers that add up to -8 and multiply to -128 are 16 and -8. So the width is either 16 inches or the width is -8 inches. The 2 things in math that will never EVER be negative are time and distance/length. So -8 is out. The width is 16 inches. That means that the length is 2(16)+31, which is 63 inches. There you go!