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Karo-lina-s [1.5K]

3 years ago

6

In the dry and hilly region of southeast Utah, many fossil remains have been uncovered. Trilobite casts, petrified bones of alli

gators, and preserved dinosaur footprints, were all found in the same location, but in different rock layers. What can we infer about the history of this region?
options:

A: this area was a gathering place for many many different types of animals.

B: ancient flooding in this region washed fossil remains into this area.

C: the Earth’s surface and climate has changed over time.

D: this region has always had hot, dry climates.

1 answer:

Anastaziya [24]3 years ago

7 0

It is B for a matter of fact

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Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

3 years ago

Bacteria that is jagged and random is called what?

Burka [1]

It is called jagged gaphene i think

6 0

3 years ago

Which statement is true of DNA polymerase?

Snezhnost [94]

Answer:

b) DNA polymerase can synthesize DNA in the 5' to 3' direction

DNA polymerase is only able to synthesize a new strand of DNA and not mRNA. It is only able to do this in the 5' to 3' direction. The leading template strand runs in the 3' to 5' direction and so the new complementary strand is synthesized in a 5' to 3' direction in one continuous run, following the replication fork as it 'unzips' the DNA.

hope it helps btw i did this test and i got it correct

check my screenshot below

please mark me brainliest

Explanation:

5 0

3 years ago

A mature plant cell is different from a mature animal cell because the plant cell has?

oksano4ka [1.4K]

Answer:

large central vacuole

Explanation:

mature plant cell contains large vacuoles while a animal cell has small vacuoles

5 0

2 years ago

Read 2 more answers

What is the difference in structure between plant and animal cells?

PIT_PIT [208]

Plant cells have cell walls, while animal cells don't have cell walls.

7 0

3 years ago

Read 2 more answers