What is the renaming fraction for 6 -3 2\5s

Please I need help with this ASAp...Thanks and will give you brainlist...

Ulleksa [173]

Answer:

Step-by-step explanation:

8 0

3 years ago

The table shows the production results for three factories. How many cars are manufactured at the fastest factory in one year?

kirill115 [55]

Answer:

16,200

Step-by-step explanation:

8 0

3 years ago

The figure Above shows the lengths of the

Molodets [167]

1. The first step here is to acknowledge the fact that opposite sides of a rectangle are equal in length, ie. the top and bottom sides are the same length, and the left and right sides are the same length. Thus, we can equate the expressions for the opposite lengths to get the following two equations:

(1) Top & bottom: 3x - y = 2x + y

(2) Left & right: 3y + 4 = 2x - 3

2. Now we need to solve the simultaneous equations for x and y. Since you have requested the substitution and elimination methods, I will show these as methods a) and b), respectively. However, first I think it will be worth combining like terms together in each of the equations. Thus:

(1) 3x - y = 2x + y

x - y = y (Subtract 2x from both sides)

x = 2y (Add y to both sides)

(2) 3y + 4 = 2x - 3

3y + 7 = 2x (Add 3 to both sides)

Now that we have combined the like terms in both equations, we can start solving for x and y.

a) Substitution method:

The substitution method relies on our rearranging one of the equations so that it has either x or y as the subject. Since we have combined the like terms together, we have already rearranged equation (1) so that x is the subject, thus we can substitute equation (1) into equation (2):

3y + 7 = 2x

if x = 2y:

3y + 7 = 2(2y) (Substitute x with 2y)

3y + 7 = 4y (2*2y = 4y)

7 = y (Subtract 3y from both sides)

Thus, y = 7. Now, we can substitute this back into equation (1) to find the value of x (note that we could also substitute this into equation 2, I have simply chosen equation 1 since there is less working involved):

x = 2y

if y = 7:

x = 2*7 = 14

Therefor, we have x = 14 and y = 7.

b) The elimination method relies on our 'eliminating' either x or y from the equations by either subtracting them or adding them together. Let us remind ourselves of our equations:

(1) x = 2y

(2) 3y + 7 = 2x

We can see here that we will need to multiply both sides of one, or both, of the equations by a particular value in order to eliminate one of the terms (since in one equation there is x and the other 2x, and in one there is 2y and the other 3y). Choosing to eliminate x will only require us to multiply equation (1) by 2, however if we were to choose to eliminate y, we would have to multiply equation (1) by 3 and equation (2) by 2 (so that each equation has 6y in it - this is their common multiple).

Given that the first option requires less working, I will choose to eliminate x. Thus, if we multiply both sides of equation (1) by 2 we get:

x = 2y

2x = 4y (Multiply both sides by 2)

Thus our two equations now become:

(1) 2x = 4y

(2) 2x = 3y + 7 (here I have simply rearranged equation 2 so that it is simpler to see how the two sides will be subtracted)

Now, we can subtract the left and right sides of each equation from the other (note that we would add them if we had one positive and one negative value so that -2x + 2x = 0).

Thus, subtracting the left and right sides of each equation, we get:

2x - (2x) = 4y - (3y + 7)

0 = 4y - 3y - 7 ( -(3y + 7) = -3y - 7 ; note that in the previous line it is very important to include the brackets around 3y - 7 )

0 = y - 7 (4y - 3y = y)

7 = y (Add 7 to both sides)

Now that we know that y = 7, we can substitute this back into equation (1) to find the value of x:

2x = 4(7)

2x = 28 (4*7 = 28)

x = 14 (28/2 = 14)

Thus, x = 14 and y = 7. This is the same answer that we found when using the substitution method - this is always a good way to check that you are on track.

3. Going back to the question, we can see that we are required to find the values of x and y, as well as the area of the rectangle. Since we have already found that x = 14 and y = 7, we can now calculate the area of the rectangle.

The area of a rectangle is given by the following formula:

A = lw, where l is the length of the rectangle and w is the width.

So far, we do not have the actual length and width of the rectangle, thus this is the next thing we must find. To do so, we must choose one of the expressions for the length (ie. top or bottom) and one for the width (ie. left or right), and substitute x = 14 and y = 7 into them.

I will choose the expression for the bottom length (2x + y) and the expression for the right length (2x - 3). Note that it wouldn't matter which of the expressions for the opposite sides you choose as they are of equal length.

(i) Calculating length:

l = 2x + y

if x = 14 and y = 7:

l = 2(14) + 7

l = 28 + 7

l = 35

(ii) Calculating width:

w = 2x - 3

if x = 14:

w = 2(14) - 3

w = 28 - 3

w = 25

Thus, the length of the rectangle is 35 cm and the width is 25 cm.

Now we are at the final step! Remember that the area of a rectangle may be described by the formula A = lw. We now know that l = 35 and w = 25, thus all that is left is to substitute these two values into the given formula. Thus:

A = lw

if l = 35 and w = 25:

A = 35*25

A = 875 cm^2

4. Thus, x = 14 and y = 7, and the area of the rectangle is 875 cm^2.

3 0

3 years ago

What is the easiest way to solve negative fractions plus positive fractions?

katen-ka-za [31]

Answer:

Step-by-step explanation:

and I'll explain why so when when we're

looking into combining fractions

positive negative fractions the main

important thing we need to make sure we

have is like denominators

all right common dinar common

denominator the easiest the easiest way

to find a common denominator is to

multiply the denominators right that's

the easiest way to go ahead and find one

just multiply three times eight which is

24 that's gonna give you your comments

and on there does that make sense so

make sense multiply the denominator but

that's not always going to be the least

common denominator so an easy way to

always check to find the least common

denominator is choose the largest

denominator which would be 8 and then

kind of list out the multiples so is and

sitting determine it does 3 divide into

any of those multiples before we get to

24 so just 3 to buy an 8 no so 8 is not

the least common denominator then we go

to 16 just 3 divided into 16 No

24 yes it does so actually end up 3

times 8 is gonna equal 24 and it's okay

lays knowing if you always want to

multiply your denominators you can

always do that but that just because

you're multiplying you're not always

gonna get the least common denominator

and the problem with that is you're

gonna have to simplify your fraction a

little bit more at the end all right but

it is also a way to always get a common

denominator so my lcd is 24 and what I

like you guys to do is always like write

that down so you can always kind of

remember it and basically when we have

an LCD of 24 what we want to be able to

do is say alright what do I need to

multiply now both of my denominators by

to get to 24 well to get 3 forget about

the negative sign per second for do get

3 we need to multiply by 8 right but

there's a problem if you have a fraction

and you only multiply the denominator by

it you've now changed the fraction think

about 1/2 if you have 1/2 and you

multiply the denominator by 3 you now

have 1/6 right is 1/6 equal to 1/2

no so we need to multiply the numerator

and the denominator by 8 think about

again 1/2 times 3 over 3 equals 3 over 6

is 3 over 6 equivalent to 1/2 yes so

when you're multiplying your fraction we

want to make sure we

keep equivalent fractions for 3/8 we

need to multiply by five over five and

then when I multiply fractions I just

simply multiply across numerator times

numerator denominator times denominator

therefore I get negative 8 over 24 plus

I don't know 3 right thank you I don't

know I was like off in my own world I

guess there you go

sorry so therefore now I have negative 8

24 plus 9 over 24 and now when we need

to add combined fractions we need to

combine fractions as long as they have

common denominators we just add or

subtract our numerators so just think

about negative you owe eight dollars you

have nine dollars in your pocket

therefore you're gonna have one dollar

left right and you keep the denominator

the same question okay letting it

internalize

7 0

3 years ago

Can someone sub to my youttube channel pls, its called Yakobu, it would really help out :)

loris [4]

Sure :)

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5 0

3 years ago