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galina1969 [7]
3 years ago
8

Solve 16x^2-9=16 and y^3-1=7 show work.

Mathematics
2 answers:
Gennadij [26K]3 years ago
6 0
16x^2-9=16
16x^2=25
x^2=25/16
x=1.25, -1.25

y^3-1=7
7^3=8
y=2

Hope this helps!
mars1129 [50]3 years ago
5 0
Here you go. Answer is in the Image.

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What to the power of 4 equals 256
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The answer to that problem is 4. 4*4*4*4=(4*4)*(4*4)=16*16=256. I hope this helped!
4 0
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Ms. chen is getting a new tile floor for her workshop. Her workshop is 15ft long and 11ft wide.
ANTONII [103]
A cause you just gotta think about it and realize you got it
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3 years ago
Given the function f(x)=3x+5a / x^2-a^2 find the value of a for which f'(12) = 0
maria [59]
The function, as presented here, is ambiguous in terms of what's being deivded by what.  For the sake of example, I will assume that you meant

           3x+5a
<span> f(x)= ------------
</span>          x^2-a^2

You are saying that the derivative of this function is 0 when x=12.  Let's differentiate f(x) with respect to x and then let x = 12:

             (x^2-a^2)(3) -(3x+5a)(2x)
f '(x) = ------------------------------------- = 0 when x = 12
                [x^2-a^2]^2

(144-a^2)(3) - (36+5a)(24)
------------------------------------  =  0
               [   ]^2

Simplifying,

(144-a^2) - 8(36+5a) = 0

144 - a^2 - 288 - 40a = 0

This can be rewritten as a quadratic in standard form:

-a^2 - 40a - 144 = 0, or a^2 + 40a + 144 = 0.

Solve for a by completing the square:

a^2 + 40a + 20^2 - 20^2 + 144 = 0
        (a+20)^2    = 400 - 144 = 156

        Then a+20 = sqrt[6(26)] = sqrt[6(2)(13)] = 4(3)(13)= 2sqrt(39)

         Finally, a = -20 plus or minus 2sqrt(39)

You must check both answers by subst. into the original equation.  Only if the result(s) is(are) true is your solution (value of a) correct.
6 0
4 years ago
What is the sum of the geometric sequence 3,15,75... if there are 7 terms ?
FinnZ [79.3K]

Answer:

58593

Step-by-step explanation:

The sum to n terms of a geometric sequence is

S_{n} = \frac{a(r^n-1)}{r-1}

where a is the first term and r the common ratio

r = 15 ÷ 3 = 75 ÷ 15 = 5 and a = 3, hence

S_{7} = \frac{3(5^7-1)}{5-1}

= \frac{3(78125-1)}{4} = \frac{3(78124)}{4} = 58593

6 0
3 years ago
If the function f(x) = (2x - 3)2 is transformed to g(x) = (-2x - 3), which type of transformation occurred?
san4es73 [151]

Answer:

A. horizontal reflection

Step-by-step explanation:

Given:

f(x)=(2x-3)^2

g(x)=(-2x-3)^2

To identify the type of transformation.

Solution:

On close observation of the functions we find the that sign of x has changed in g(x) with other terms being constant.

<em>Thus, the transformation statement can be given as:</em>

f(x)\rightarrow f(-x)

As:

f(x)=(2x-3)^2

f(-x)=(2(-x)-3)^2= (-2x-3)^2 = g(x)

The transformation f(x)\rightarrow f(-x) describes horizontal reflection of function across the y-axis.

Thus, f(x)  is horizontally reflected across y-axis to get g(x).

8 0
4 years ago
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