Answer:

Step-by-step explanation:
The equation for a tangent line of f(x) in the point (a,f(a)) can be calculated as:
L(x) = f(a) + f'(a)(x-a)
Where L(x) is also call a linear approximation and f'(a) is the value of the derivative of f(x) in (a,f(a)).
So, the derivative of f(x) is:

Then, to find the linear approximation we are going to use the point (16, f(16)). So a is 16 and f(a) and f'(a) are calculated as:

Then, replacing the values, we get that the equation of the tangent line in (16,4) is:

Finally, the approximation for
is:

Y=mx+b
where m is the slope and b is the y intercept
Answer:
idk i kinda forgot what was the answer let me go check
The first step is to find the slope which is (y2-y1)/(x2-x1) and you can use any of these points. Next write the equation is point slope form which is y-y1=m(x-x1) using the slope and one of the points. Then you can simplify to write this is slope-intercept form and solve the x and y intercepts as given.