Step-by-step explanation:
(a + b)² = 9
(b + c)² = 25
(a + c)² = 81
Taking the square root:
a + b = ±3
b + c = ±5
a + c = ±9
By adding these three equations together and dividing both sides by 2, we get the value of a + b + c.
Possible combinations for a + b + c such that the sum is greater than or equal to 1 are:
a + b + c = (-3 + 5 + 9)/2 = 11/2
a + b + c = (3 − 5 + 9)/2 = 7/2
a + b + c = (3 + 5 + 9)/2 = 17/2
<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
Answer:
7 x 7 x 17 =833
Step-by-step explanation:
833in^3
Step-by-step explanation:
8x + 6) - (x + 4)
8x + 6 - (x + 4)
8x + 6 - x - 4
7x + 2
Answer:
yes it sucks. but yet we still use it
Step-by-step explanation:
