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spayn [35]
3 years ago
15

What is he rate of change of a line that passes through the points (7,-1) and (-1,5)

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0
Hello! thanks for asking this question! -0.75 should be your answer. Please tell me if I was right!
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What is the value of x? Leave your answer in simlplest radical form.
valina [46]
Using the Pythagorean theorem,
.. x^2 = 3^2 +3^2 = (3^2)*2
.. x = √((3^2)*2)
.. x = 3√2 . . . . . . . . matches selection (a)

_____
The hypotenuse of an isosceles right triangle is always √2 times the length of either leg. Since the legs are 3, the hypotenuse is 3√2. You only need to remember this fact to save a bunch of arithmetic.
4 0
3 years ago
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point f lies on eg and point m lies on en. If f, e and m are collinear, what must be true of these rays?
andrey2020 [161]

All of the rays indicated coincide. The points lie on the same line or ray. For explanation, please refer to the attachment.


8 0
3 years ago
Read 2 more answers
In triangle STU, u2 = s2 + t2.
sineoko [7]

Answer:

(B) The measure of angle SUT is equal to 90 degrees

Step-by-step explanation:

It is given that in In triangle STU, u^2=s^2+t^2.

We can see from the triangle and also the given condition that the triangle will be right triangle as it is satisfying the Pythagoras theorem.

(Hyp)^2=(Base)^2+(Perpendicular)^2

that is:

u^{2}=s^{2}+t^{2}

where u is the hypotenuse, s is the base and t is the perpendicular.

Thus, the angle SUT should be of 90°.

Thus, The measure of angle SUT is equal to 90 degrees.

Hence, option B is correct.

3 0
3 years ago
What 2 pieces of mathematical information do a table, a graph, and an equation have in common?
Gala2k [10]

Answer:

Trends:

In the graph or a table you easily can see trends in the data, for example, parts where if x increases also does y, or things like that.

Of course you, with some mathematical knowledge, also can notice those things when you have the equation, so this is a thing that the 3 have in common.

Range:

You usually can see the whole range (all the possible y values) of your equation by looking at the graph or the data set. And obviously, if you have the equation you can easily find the range of it.

3 0
4 years ago
How do you do this question?
irga5000 [103]

Answer:

π/6 [37^(³/₂) − 1] ≈ 117.3187

Step-by-step explanation:

The surface area is:

S = ∫ 2π (x − 0) √(1 + (dx/dy)²) dy

0 ≤ x ≤ 3, so -4 ≤ y ≤ 5.

Find dx/dy.

y = 5 − x²

x² = 5 − y

x = √(5 − y)

dx/dy = ½ (5 − y)^(-½) (-1)

dx/dy = -½ (5 − y)^(-½)

(dx/dy)² = ¼ (5 − y)^(-1)

(dx/dy)² = 1 / (4 (5 − y))

Plug in:

S = ∫₋₄⁵ 2π x √(1 + 1 / (20 − 4y)) dy

S = ∫₋₄⁵ 2π √(5 − y) √(1 + 1 / (4 (5 − y))) dy

S = ∫₋₄⁵ 2π √((5 − y) + 1/4)) dy

S = ∫₋₄⁵ 2π √(5.25 − y) dy

If u = 5.25 − y, then du = -dy.

S = ∫ 2π √u (-du)

S = -2π ∫ √u du

S = -2π (⅔ u^(³/₂))

S = -4π/3 u^(³/₂)

Substitute back:

S = -4π/3 (5.25 − y)^(³/₂)

Evaluate between y=-4 and y=5.

S = [-4π/3 (5.25 − 5)^(³/₂)] − [-4π/3 (5.25 − -4)^(³/₂)]

S = -4π/3 (0.25)^(³/₂) + 4π/3 (9.25)^(³/₂)

S = π/6 [37^(³/₂) − 1]

S ≈ 117.3187

5 0
3 years ago
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