She sold 74 child tickets and 126 adult tickets
Step-by-step explanation:
Stacy is selling tickets for the school play
- She has a total of 200 seats available, and there will be two types of tickets offered, child and adult tickets
- She sold each child ticket for $6 , each adult ticket for $10 , and made a total of $1704
We need to find how many of each ticket she sold
Assume that x is the number of child tickets and y is the number of the adult tickets
∵ She has a total of 200 seats available
∵ She sold x child tickets
∵ She sold y adult tickets
- Add x and y, then equate the sum by 200
∴ x + y = 200 ⇒ (1)
∵ She sold each child ticket for $6
∵ She sold each adult ticket for $10
∵ She made a total of $1704
- Multiply x by 6 and y by 10, then add the products and
equate them by 1704
∴ 6x + 10y = 1704 ⇒ (2)
Now we have a system of equation to solve it
Multiply equation (1) by -10 to eliminate y
∵ -10x - 10y = -2000 ⇒ (3)
- Add equations (2) and (3) to find x
∴ -4x = -296
- Divide both sides by -4
∴ x = 74
- Substitute the value of x in equation (1) to find y
∵ 74 + y = 200
- Subtract 74 from both sides
∴ y = 126
She sold 74 child tickets and 126 adult tickets
Learn more:
You can learn more about the system of equations in brainly.com/question/2115716
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