If cos theta = 1/4 and 0 degrees, find tan theta

Mathematics

1 answer:

Zina [86]3 years ago

8 0

What? Sorry can’t understand

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Please answer this correctly for a brainliest ☺️

Dimas [21]

Hello I think the answer would be three.

5 0

3 years ago

Help! Urgent request

TiliK225 [7]

Answer: 6 students

What we know:

Students: 24

Students who play checkers: $\frac{2}{3}$

Students who also play sudoku: $\frac{3}{8}$ of the $\frac{2}{3}$

24 ÷ 3 = 8, so 8 × 2 = 16 (students who play checkers)

$\frac{3}{8}$ × 2 = $\frac{6}{16}$

So the answer is,

6 students play both checkers and sudoku

8 0

3 years ago

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Camden is going to invest $600 and leave it in an account for 12 years. Assuming the

UkoKoshka [18]

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}$

$920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r$