In my calculation is divide it 0.00018333333
and if multiply it well be 6600
Correct answer is: (0,7843) and (10,8793)
Solution:-
Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.
We have to write this data as (x,y) .
Where x= years after 1990 and y=number of students enrolled.
Since in 1990, 7843 students enrolled, x = 1990-1990=0
And y=7843.
Hence one ordered pair is (0,7843).
Let us find the years after 1990 for 2000 = 2000-1990 =10
Hence another ordered pair is (10,8793).
Twenty-one thousand and sixty-three divided by three is 7021
First, take any number (for this example it will be 492) and add together each digit in the number (4+9+2 = 15). Then take that sum (15) and determine if it is divisible by 3. The original number is divisible by 3 (or 9) if and only if the sum of its digits is divisible by 3 (or 9).If a number is a multiplication of 3 consecutive numbers then that number is always divisible by 3. This is useful for when the number takes the form of (n * (n - 1)*(n + 1))Example: 492 (The original number). 4 + 9 + 2 = 15 (Add each individual digit together). 15 is divisible by 3 at which point we can stop. Alternatively we can continue using the same method if the number is still too large: 1 + 5 = 6 (Add each individual digit together). 6 ÷ 3 = 2 (Check to see if the number received is divisible by 3). 492 ÷ 3 = 164 (If the number obtained by using the rule is divisible by 3, then the whole number is divisible by 3)
Answer:
C
Step-by-step explanation:
