As we know that cotx= 1/tanx
cot36° = 1/tan36°
=>cot36°= 1/0.726543
=>so cot 36°= 1.376382
So correct answer is option D.
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In the paper airplane, ABCD ≅ EFGH, m∠B = m∠BCD = 90, and m∠BAD = 143. Find m∠FEH.
1 answer:
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As we know that cotx= 1/tanx
cot36° = 1/tan36°
=>cot36°= 1/0.726543
=>so cot 36°= 1.376382
So correct answer is option D.
HOPR YOU LIKED.
