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3 years ago

I need help fast Pleeeease! Find and Factor the GCF: 4y^3-2y^2

2 answers:

fomenos3 years ago

6 0

4y^3 - 2y^2

what is the largest number that divides evenly into 4y^3 and -2y^2?
it is 2

what is the highest degree of y that divides evenly into 4y^3 and -2y^2
it is y^2

the GCF is 2y^2

2y^2(2y - 1) <<<< answer

hope that helps, God bless!

Galina-37 [17]3 years ago

3 0

The answer is 0
why the answer is zero is because
<span>4y3 + -2y2 = 0
-2y2 + 4y3 = 0 'y'.
, '2y2'. 2y2(-1 + 2y) = 0</span>

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How to find the square root of complex numbers?? Find the square root of (6+8i) ??

ivann1987 [24]

Answer:

$2 \sqrt{2} + i \sqrt{2}$

Step-by-step explanation:

The square of a complex number is a complex number. Here, we have:

${(a + bi)}^{2} = 6 + 8i$

${a}^{2} + 2abi - {b}^{2} = 6 + 8i$

We then have this system of equations:

${a}^{2} - {b}^{2} = 6$

$2ab = 8$

Solving this system:

$ab = 4$

$b = \frac{4}{a}$

${a}^{2} - {( \frac{4}{a}) }^{2} = 6$

${a}^{2} - \frac{16}{ {a}^{2} } = 6$

${a}^{4} - 16 = 6{a}^{2}$

${a}^{4} - 6 {a}^{2} - 16 = 0$

$( {a}^{2} - 8)( {a}^{2} + 2) = 0$

${a}^{2} = 8$

$a = 2 \sqrt{2}$

$b = \frac{4}{2 \sqrt{2} } = \sqrt{2}$

6 0

2 years ago

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Calculate the value of each expression:<br> (-8)•(-2/3)<br> SHOW YOUR WORK:

inna [77]

Answer: $\frac{16}{3}$

Step-by-step explanation:

For this exercise it is important to remember the multiplication of signs:

$(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-$

In this case, given the following expression:

$(-8)(-\frac{2}{3})$

You can idenfity that both factors are negative. Then, the product (The result of the multiplication) will be positive.

Then, in order to get the product, you need to multiply the numerator of the fraction by -8. So, you get:

$\frac{(-2)(-8)}{3}=\frac{16}{3}$

You can notice that the numerator and the denominator of the fraction obtained cannot be divided by the same number; therefore, the fraction cannot be simplified.

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3 years ago

It is the one closest to the top plz Help

s344n2d4d5 [400]

Answer:

3.6 ft

Step-by-step explanation:

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2 years ago

The vertices of xyz are x (1,-4)

dexar [7]

Answer:

5. The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

6. The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

Step-by-step explanation:

If the point (x, y) translated by T → (h, k), then its image is (x + h, y + k)

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (-4, -3)

∴ h = -4 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + -4, -4 + -3)

∴ X' = (-3, -7)

∵ Y' = (-2 + -4, -1 + -3)

∴ Y' = (-6, -4)

∵ Z' = (3 + -4, 1 + -3)

∴ Z' = (-1, -2)

∴ The vertices of ΔX'Y'Z' are (-3, -7), (-6, -4), (-1, -2)

In ΔXYZ

∵ X = (1, -4), Y = (-2, -1), Z = (3, 1)

∵ T → (5, -3)

∴ h = 5 and k = -3

→ Use the rule above to find the image of the vertices of the Δ

∵ X' = (1 + 5, -4 + -3)

∴ X' = (6, -7)

∵ Y' = (-2 + 5, -1 + -3)

∴ Y' = (3, -4)

∵ Z' = (3 + 5, 1 + -3)

∴ Z' = (8, -2)

∴ The vertices of ΔX'Y'Z' are (6, -7), (3, -4), (8, -2)

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3 years ago

What is my slope if the rise over run is 3/5?

Alborosie

Your slope will be 3/5 or 0.6.

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3 years ago

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