Answer: she must complete 4 levels to have a point fewer than 20
Step-by-step explanation:
Given the following :
Starting point = 100 points
Passing a level = - 8 points
Catching a flower = - 3 points
Suppose Tina catches 6 flowers per level
Number of levels she must complete to have fewer Than 20 points
Total number of points lost per level:
Catching 6 flowers = -(6 × 3)
Passing the level = - 8
= - 18 + - 8 = - 26 points
Number of levels she must complete to have < 20
Let number of levels = y
Starting points - (26 × number of levels) < 20
100 - (26y) < 20
100 - 26y < 20
-26y < 20 - 100
-26y < - 80
y > 80/26
y > 3.07
Hence she must complete 4 levels to have a point fewer than 20
Answer:
Continues variables
Step-by-step explanation:
A continuous variable is the one that takes an exact value in a continuous range. Always between 2 observable values, there are going to exit a third intermedium value that the variable can take.
Answer:
60
Step-by-step explanation:
Answer:
∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° , ∠KLJ = 86°
Step-by-step explanation:
Here, given In ΔJLK and ΔMLP
Here, JK II ML, LM = MP
∠JLM = 22° and ∠LMP = 36°
Now, As angles opposite to equal sides are equal.
⇒ ∠MLP = ∠MPL = x°
Now, in ΔMLP
By <u>ANGLE SUM PROPERTY</u>: ∠MLP + ∠MPL + ∠LMP = 180°
⇒ x° + x° + 36° = 180°
⇒ 2 x = 180 - 36 = 144
or, x = 72°
⇒ ∠MLP = ∠MPL = 72°
Now,as JK II ML
⇒ ∠LJK = ∠JLM = 22° ( Alternate pair of angles)
Now, by the measure of straight angle:
∠MLP + ∠JLM + ∠JLK = 180° ( Straight angle)
⇒ 72° + 22° + ∠JLK = 180°
or, ∠JLK = 86°
In , in ΔJLK
By <u>ANGLE SUM PROPERTY</u>: ∠JKL + ∠JLK + ∠LJK = 180°
⇒ ∠JKL + 86° + 22° = 180°
⇒ ∠JKL = 180 - 108 = 72 , or ∠JKL = 72°
Hence, from above proof , ∠MLP = 72° , ∠LJK = 22° , ∠JKL = 72° ,
∠KLJ = 86°
