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lianna [129]
4 years ago
13

A teacher is experimenting with computer-based instruction. In which situation could the teacher use a hypothesis test for a dif

ference in two population means? (i) She gives each student a pretest. Then she teaches a lesson using a computer program. Afterwards, she gives each student a posttest. The teacher wants to see if the difference in scores will show an improvement. (ii) She randomly divides the class into two groups. One group receives computer-based instruction. The other group receives traditional instruction without computers. After instruction, each student has to solve a single problem. The teachers wants to compare the proportion of each group who can solve the problem. (iii) She gives each student a pretest. She then randomly divides the class into two groups. One group receives computer-based instruction. The other group receives traditional instruction without computers. After instruction, each student takes a post-test. The teacher compares the improvement in scores (post-test minus pretest) in the two groups. (iv) The teacher uses a combination of traditional methods and computer-based instruction. She asks students which they liked better. She wants to determine if the majority prefer the computer-based instruction.

Mathematics
2 answers:
Pavlova-9 [17]4 years ago
3 0

Answer:

Step-by-step explanation:

find the solution below

Strike441 [17]4 years ago
3 0

Answer:

(i) She gives each student a pretest. Then she teaches a lesson using a computer program. Afterwards, she gives each student a posttest. The teacher wants to see if the difference in scores will show an improvement.

Step-by- Step

The situation is a case of matched or paired samples since the samples are dependent. The two measurements are drawn from the same pair of individuals The parameter that is tested using matched pairs is the population mean and this is what teacher intends to use a hypothesis test for.

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So for this, we will be simplifying √180 and √125 using the product rule of radicals (√ab = √a * √b)


Starting with √180: \sqrt{180}=\sqrt{10} *\sqrt{18} =\sqrt{5} *\sqrt{2}*\sqrt{9} *\sqrt{2}=3*2*\sqrt{5} =6\sqrt{5}


Now with √125: \sqrt{125}=\sqrt{25}*\sqrt{5} =5\sqrt{5}



Now that we have our simplified radicals, our equation looks like this: 6√5 - 5√5 + √5 . Combine everything, and your answer will be 2√5.

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The graph is a function. When drawing a vertical line, there will be two circumstances:

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For the first circumstance, the graph that has only one intersect with a line - it is a function. For the second circumstance, the graph cannot be a function as it gives more than one y-value for a single x-value.

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