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mariarad [96]
4 years ago
10

Which description best describes the graph?

Mathematics
2 answers:
marysya [2.9K]4 years ago
8 0

Answer: Hello there!

Let's analyze the graph.

The first thing you can see is that when x increases, y decreases. This means that our function is decreasing.

Now we need to see if it is linear or nonlinear. You can see that the function starts decreasing slowly and it gets sharper when x grows (in the graph you can see a little curve). A linear function is graphed with a straight line, and we can see that is not this case, then our function is nonlinear.

So the correct answer is Nonlinear decreasing, the fourth option.

8_murik_8 [283]4 years ago
4 0
Its nonlinear decreasing.

hope this helps you
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Help! Just a little more
riadik2000 [5.3K]

Answer:

x = 7

y = 8

Step-by-step explanation:

4y-4 = 28

4y = 32

y = 8

10x+65 = 135

10x = 70

x = 7

3 0
3 years ago
Read 2 more answers
Scientist finds that for every in of rainfall at a lake, the level of the
Serga [27]

Answer:

0.8 cm

Step-by-step explanation:

I divided 0.6 by 3 and then multiplied by 4 because 0.6 is 3/4 of the portion and we need the other 1/4.

8 0
3 years ago
Maximize x and y. P=3x +2y
Natalka [10]

P = 3x + 2y

There is an accompanying graph in this problem. In the graph, there are 4 points to consider. I'll just assign letters on each point.

Point O is found in x = 0 ; y = 0 or (0,0)

Point A is found in x = 8 ; y = 0 or (8,0)

Point B is found in x = 6 ; y = 5 or (6,5)

Point C is found in x = 0 ; y = 8 or (0,8)

We will substitute x and y in the equation by its values per point.

Point A = 3(8) + 2(0) = 24 + 0 = 24

Point B = 3(6) + 2(5) = 18 + 10 = 28

Point C = 3(0) + 2(8) = 0 + 16 = 16 

The maximum value of the function P = 3x+2y is 28 and its minimum value is 16.

6 0
1 year ago
P(6,0) under the translation (x -6, y -1) ?
tatiyna
It would probably be -6 -1
5 0
3 years ago
Let a and b be 3 Ã 3 matrices with det(a) = 4 and det(b) = 5. find the value of (a) det(ab)
Georgia [21]
(a) |AB| = |A| |B| = -1 * 2 = -2. 

<span>(b) |B^5| = |B|^5 = 2^5 = 32. </span>

<span>(c) Since A is 4 x 4, </span>
<span>|2A| = 2^4 * |A| = 16 * -1 = -16. </span>

<span>(d) Since determinants are invariant under transposition, </span>
<span>|A^t A| = |A^t| |A| = |A| |A| = (-1)(-1) = 1. </span>

<span>(e) |B^(-1) AB| = |B^(-1)| |A| |B| </span>
<span>.....................= (1/|B|) |A| |B| </span>
<span>.....................= |A| </span>
<span>.....................= -1. </span>

<span>I hope this helps!</span>
6 0
4 years ago
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