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expeople1 [14]
3 years ago
5

on square bcde if e is located at (4,-9) and d is located at (10,-5) find the perimeter of the square

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

  • 8\sqrt{13} units

Step-by-step explanation:

<u>We know that:</u>

  • P = 4a

<u>We can find one side by distance formula:</u>

  • a = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • a = \sqrt{(10 - 4)^2+(-5+9)^2} = \sqrt{36+16} = \sqrt{52} = 2\sqrt{13}

<u>Then the perimeter is:</u>

  • P = 4*2\sqrt{13} = 8\sqrt{13} units
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Name the property shown in the equation: 4 x (5 + 6) = (4 x 5) + (4 x 6)
Novosadov [1.4K]

The property used in the equation is called Distributive property.

<h3>What is Distributive property?</h3>

The distributive Property States that when a factor is multiplied by the sum/addition of two terms, it is essential to multiply each of the two numbers by the factor, and finally perform the addition operation.

Given an equation, 4 x (5 + 6) = (4 x 5) + (4 x 6)

The property used in this equation is distributive property.

a(b+c) = (a*b)+(a*c)

Hence, The property used in the equation is called Distributive property.

For more references on Distributive property, click;

brainly.com/question/5637942

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8 0
1 year ago
1.905 rounded to the nearest tenth
Tema [17]
1.905 rounded to the nearest tenth is 1.9
4 0
3 years ago
Find the value of t.
zaharov [31]

Answer:

t =12 m

Step-by-step explanation:

We can use similar triangles and proportions to solve this problem.

Put the smaller triangle on top and the larger triangle on bottom

12         9

------ = -------

16          t

Solve by using cross products

12 t = 9*16

12 t =144

Divide by 12

12t/12 = 144/12

t = 12

5 0
2 years ago
Read 2 more answers
Sin4x.sin5x+sin4x.sin3x-sin2x.sinx=0
andreev551 [17]

Recall the angle sum identity for cosine:

cos(<em>x</em> + <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) - sin(<em>x</em>) sin(<em>y</em>)

cos(<em>x</em> - <em>y</em>) = cos(<em>x</em>) cos(<em>y</em>) + sin(<em>x</em>) sin(<em>y</em>)

==>   sin(<em>x</em>) sin(<em>y</em>) = 1/2 (cos(<em>x</em> - <em>y</em>) - cos(<em>x</em> + <em>y</em>))

Then rewrite the equation as

sin(4<em>x</em>) sin(5<em>x</em>) + sin(4<em>x</em>) sin(3<em>x</em>) - sin(2<em>x</em>) sin(<em>x</em>) = 0

1/2 (cos(-<em>x</em>) - cos(9<em>x</em>)) + 1/2 (cos(<em>x</em>) - cos(7<em>x</em>)) - 1/2 (cos(<em>x</em>) - cos(3<em>x</em>)) = 0

1/2 (cos(9<em>x</em>) - cos(<em>x</em>)) + 1/2 (cos(7<em>x</em>) - cos(3<em>x</em>)) = 0

sin(5<em>x</em>) sin(-4<em>x</em>) + sin(5<em>x</em>) sin(-2<em>x</em>) = 0

-sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) (sin(4<em>x</em>) + sin(2<em>x</em>)) = 0

Recall the double angle identity for sine:

sin(2<em>x</em>) = 2 sin(<em>x</em>) cos(<em>x</em>)

Rewrite the equation again as

sin(5<em>x</em>) (2 sin(2<em>x</em>) cos(2<em>x</em>) + sin(2<em>x</em>)) = 0

sin(5<em>x</em>) sin(2<em>x</em>) (2 cos(2<em>x</em>) + 1) = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   2 cos(2<em>x</em>) + 1 = 0

sin(5<em>x</em>) = 0   <u>or</u>   sin(2<em>x</em>) = 0   <u>or</u>   cos(2<em>x</em>) = -1/2

sin(5<em>x</em>) = 0   ==>   5<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   5<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   5<em>x</em> = 2<em>nπ</em>   <u>or</u>   5<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = 2<em>nπ</em>/5   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/5

sin(2<em>x</em>) = 0   ==>   2<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>

… … … … …   ==>   2<em>x</em> = 2<em>nπ</em>   <u>or</u>   2<em>x</em> = (2<em>n</em> + 1)<em>π</em>

… … … … …   ==>   <em>x</em> = <em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>/2

cos(2<em>x</em>) = -1/2   ==>   2<em>x</em> = arccos(-1/2) + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -arccos(-1/2) + 2<em>nπ</em>

… … … … … …    ==>   2<em>x</em> = 2<em>π</em>/3 + 2<em>nπ</em>   <u>or</u>   2<em>x</em> = -2<em>π</em>/3 + 2<em>nπ</em>

… … … … … …    ==>   <em>x</em> = <em>π</em>/3 + <em>nπ</em>   <u>or</u>   <em>x</em> = -<em>π</em>/3 + <em>nπ</em>

<em />

(where <em>n</em> is any integer)

5 0
2 years ago
Find the volume of this figure and show your work
mario62 [17]

Answer:

10

Step-by-step explanation:

The answer is 10 because there are five stacks of 2 cubes. 5 x 2 = 10.

4 0
3 years ago
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